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17 Sep 2019, 11:28
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C
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Difficulty:
75%
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Question Stats:
57% (02:13) correct
43%
(02:26)
wrong
based on 300
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Two people are walking around a circular track. They start at 8 A.M. from the same point but travel in opposite directions. The first person walks at a speed of two rounds per hour and the second person walks at a speed of three rounds per hour. How many times will they cross each other before the clock shows 9:30 A.M.?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
17 Sep 2019, 19:21
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Hovkial
Combined, they complete 2+3 or 5 rounds in one hour..
Whenever they meet each other, they would have completed one round within themselves, so 5 rounds in 1 hr means they meet 5 times in 1 hr..
If in 1 hr they complete 5 rounds, then in 8:00 - 9:30 am, that is 1.5 hr, they will complete 5*1.5 = 7.5 rounds..
So, they would have met 7 times and on the way to meet 8th time
C
General Discussion
17 Sep 2019, 11:45
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First person's speed is 1/30
and second one's is 1/20.
So, (1/20 + 1/30)×X =1
5/60*x=1
X=60/5=12
That is they meet each other first time, after 12 minutes.
9:30-8=1:30 or 90 minutes
90÷12=~7
Option C
Posted from my mobile device
and second one's is 1/20.
So, (1/20 + 1/30)×X =1
5/60*x=1
X=60/5=12
That is they meet each other first time, after 12 minutes.
9:30-8=1:30 or 90 minutes
90÷12=~7
Option C
Posted from my mobile device
