Draw a line from x to W which is perpendicular to YZ at O. Such that we have four triangles. YWO , ZWO, YXO and ZXO.
We know ‹WYX and angle WZX is 90. (Angle drawn from centre to tangent.)
XY and XZ are equal. Tangent drawn from same outside point.
Also YZ is a chord.
The triangle WYX and WZX
YW = WZ ( radius)
XW common.
YX= ZX (tangents)
Therefore angle yxw = zxw -----(1)
Since XW cut YZ at 90°
In ∆ OYX and ∆ OZX
yxw = zxw (proved above)
Angel xoy = xoz = 90
Xy = Xz ( tangents)
So ∆ OYX and ∆ OZX are equal, YO and ZO are equal = 60 each and right angle triangle
Using Pythagoras,
XY^2 = XO^2+YO^2
156^2-60^2=YO^2
YO = 144 ------(2)
Draw a triangle with YZ as base and tip on the circle. The third side be V
Angle OYX = angle YVZ (angel drawn between tangent and the chord is equal to the angle drawn by chord at the circle)
2* Angle YVZ = angle YWZ
(Angle at the centre is twice the angle at circle.)
Angle YWX = 2*(Angle YWO)
Now in triangle YWO and YXO
Angle OYX = angle YWO
Angle WXO is = angle OXY
YOW= YOX = 90
Both triangle are similar
Therefore using similar triangle property,
YO/OX = WY/XY
60/144 = WY/156
WY = 60*156/144 = 65
WY = 65 (radius)
Answer is B
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