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jackfr2
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The basic things to understand here are:
1) Since the two trains start together, they must have travelled for the same time period till they meet at a point.
2) the distance travelled by A before they met = distance travelled by B after they met.
The distance travelled by A after they met = distance travelled by B before they met.
Let the time for which they both travelled before they met be t1.

:1) Sa.16 = Sb.t1 and 2) Sa.t1= Sb.9
Dividing equation 1) with equation 2) :
16/t1 = t1/9 ; t1= 12 hrs.
Put t1=12 in any equation.

We get Sb= 160

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What's this method/formula called?
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jackfr2
Two trains A and B start simultaneously in the opposite direction from two points P and Q and arrive at their destinations(Q and P) 16 and 9 hours respectively after their meeting each other. At what speed does the second train B travel if the first train travels at 120 kmph

A. 90 kmph
B. 200 kmph
C. 240 kmph
D. 160 kmph
E. 360 kmph

\(S_A/S_B = √(t_B/t_A)\)

\(120/S_B = √(9/16)\)

\(S_B = 160\)

Answer: Option D
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Divyanshu14
What's this method/formula called?
GMATinsight
jackfr2
Two trains A and B start simultaneously in the opposite direction from two points P and Q and arrive at their destinations(Q and P) 16 and 9 hours respectively after their meeting each other. At what speed does the second train B travel if the first train travels at 120 kmph

A. 90 kmph
B. 200 kmph
C. 240 kmph
D. 160 kmph
E. 360 kmph

\(S_A/S_B = √(t_B/t_A)\)

\(120/S_B = √(9/16)\)

\(S_B = 160\)

Answer: Option D
I'm not sure if this formula has a name to it, but whenever two entities starting from opposite ends at the same time meet at a common point and the total distance they travelled is D, the ratio of their speeds \(\frac{Sa}{Sb} = \sqrt{\frac{Tb}{Ta}}\), where Tb and Ta is the time taken to reach their destination from the common point.

Here's another application of the same formula on a different question, along with a detailed answer / derivation: https://gmatclub.com/forum/a-and-b-are- ... l#p3463553
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