Bunuel
Two water tanks, X and Y, were drained simultaneously. If X contained 30 more gallons of water than Y, and both tanks became empty at the same time, how long did it take the tanks to empty?
(1) For ever gallon drained from tank Y, 2 gallons were drained from tank X.
(2) Tank Y was drained at a constant rate of 20 gallons per hour.
Let the two water tanks be X and Y and their capacities be x,y respectively.
X contains 30 gallons more than y. That’s x =30+y
Time to empty ???
Statement 1: (1) For every gallon drained from tank Y, 2 gallons were drained from tank X.
Rate of Y : Rate of X = 1k:2k
time of draining is same.
(y+30)/2 = y/1
solving it we get, y =30 , thus x =60. Depending on the rates we take just two cases .
case 1: Rates of x and y be 20 gallons/hour and 10 gallons/hour respectively.
Time of x =60/20 =3 hoursTime of y =30/10 =3 hourscase 2: Rates of x and y be 2 gallons/hour and 1 gallon/hour respectively.
Time of x = 60/2 =30 hoursTime of y =30/1 =30 hoursHence,
NOT SUFFICIENT.Statement 2: (2) Tank Y was drained at a constant rate of 20 gallons per hour.
With rates of y alone, we cannot calculate anything. Hence,
NOT SUFFICIENT.Combining Statements 1 and Statements 2, we get
Rate of Y : Rate of X = 1k:2k = 20: 40
time taken for y= 30/20 = 1.5 hrs.
time taken for x = 60/40 = 1.5 hrs.
Hence,
SUFFICIENT .
OPTION C