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07 Jun 2021, 06:15
Kudos
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Difficulty:
55%
(hard)
Question Stats:
83% (03:31) correct
17%
(03:29)
wrong
based on 6
sessions
History
Date
Time
Result
Not Attempted Yet
Two workers produce the same part.. For the first workers, it takes 5 minutes longer than the second worker to complete the part. Within 8 hours, the second worker produces 16 parts more than the number of parts the first worker makes. During this time period , how many parts two workers produce ?
A. 28
B. 32
C. 33
D. 45
E. 48
A. 28
B. 32
C. 33
D. 45
E. 48
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07 Jun 2021, 20:53
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Bunuel
Let the number made by slower worker be x, so the more productive worker makes x+16.
Time taken by both is 8 hrs or 480 minutes.
The difference in their time to make one unit is 5 minutes => \(\frac{480}{x}-\frac{480}{x+16}=5\)
\(480(x+16)-480(x)=5(x)(x+16)\)
\(96*16=x^2+16x\)
\(x^2+16x-48*32=0\)
\((x+48)(x-32)=0\)
So x can be 32 or -48, but x cannot be negative.
x is 32, and total they make together is 32+(32+16)=32+48=80
Bunuel, I believe, looking at the option, that question is meant to ask how much the slower one makes in 8 hours.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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