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gmatt14
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thx for your answers!
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Eden
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As I understand it, whenever there is a product of multiple of 5's and multiple of 2's , we will always end up with a last digit of zero's. Example:
5 ^1* 2^1 => last digit is 0
5^2 * 2^2 => last 2 digits are 0
so 5^19 * 2^17 will have 17 0's on the right hand side. Someone please correct me if I'm wrong... :roll:
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Eden, you are right.
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Pls. find everybody very useful the reference of hussain15 to the link
https://takshzilabeta.com/index.php?opti ... -&Itemid=5

Thank you very much Hussain!!!
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Hi all,
i was just wondering if it is always possible to use the approach of "intern" with those kind of questions?

It seems the most easiest way to me.

Many thanks
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NYC5648
Hi all,
i was just wondering if it is always possible to use the approach of "intern" with those kind of questions?

It seems the most easiest way to me.

Many thanks

Check this: math-number-theory-88376.html. Chapters: LAST DIGIT OF A PRODUCT and LAST DIGIT OF A POWER are dedicated to this subject.



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