Last visit was: 27 Apr 2026, 06:29 It is currently 27 Apr 2026, 06:29
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 27 Apr 2026
Posts: 109,928
Own Kudos:
Given Kudos: 105,914
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,928
Kudos: 811,543
 [16]
3
Kudos
Add Kudos
12
Bookmarks
Bookmark this Post
User avatar
Dev23
Joined: 28 Oct 2020
Last visit: 02 May 2025
Posts: 20
Own Kudos:
Given Kudos: 30
Posts: 20
Kudos: 24
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
stne
Joined: 27 May 2012
Last visit: 26 Apr 2026
Posts: 1,811
Own Kudos:
2,093
 [2]
Given Kudos: 681
Posts: 1,811
Kudos: 2,093
 [2]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
ThatDudeKnows
Joined: 11 May 2022
Last visit: 27 Jun 2024
Posts: 1,070
Own Kudos:
1,031
 [1]
Given Kudos: 79
Expert
Expert reply
Posts: 1,070
Kudos: 1,031
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Using each letter of the word ZEBRA only once how many one, two, three, four and five-letter words can be created ?

A. 20
B. 60
C. 100
D. 150
E. 325


How many 5-letter words? 5*4*3*2*1 = 120.
How many 4-letter words? 5*4*3*2 = 120.
That's already 240.

Answer choice E.
User avatar
Emily1122
Joined: 25 Mar 2020
Last visit: 15 Dec 2025
Posts: 25
Own Kudos:
Given Kudos: 92
Posts: 25
Kudos: 9
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel

Could you please help explain why we add?
It says "and", why do we add, not multiply?
User avatar
Baxee
Joined: 31 Jul 2023
Last visit: 16 Aug 2023
Posts: 1
Given Kudos: 1
Posts: 1
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Emily1122
Bunuel

Could you please help explain why we add?
It says "and", why do we add, not multiply?

"And" does not necesserally means you multiply. Here, you have to find how many word of 1,2,3,4,5 letters you can do with the letters given. For 1 : 6 letters (Z E B R A)
For 2 : 6 letters ( Z E B R A) and then 5, because you cannot use a letter you aleready used --> 6*5
And so on until 6
User avatar
pudu
Joined: 12 Mar 2023
Last visit: 06 Mar 2024
Posts: 229
Own Kudos:
Given Kudos: 16
Location: India
Posts: 229
Kudos: 123
Kudos
Add Kudos
Bookmarks
Bookmark this Post
single letter can taken in 5 ways.

Two letters can taken in 5C2*2!=20.
Three letters can taken in 5C3*3!=60
Four letters can taken in 5C4*4!=120
and five letters can taken in 5C5*5!=120

total=120+120+60=20+5=325

E
User avatar
Its_me_aka_ak
Joined: 16 Jul 2023
Last visit: 10 Jun 2025
Posts: 111
Own Kudos:
Given Kudos: 310
Location: India
GPA: 3.46
Posts: 111
Kudos: 21
Kudos
Add Kudos
Bookmarks
Bookmark this Post
stne
Bunuel
Using each letter of the word ZEBRA only once how many one, two, three, four and five-letter words can be created ?

A. 20
B. 60
C. 100
D. 150
E. 325

\(1\) letter words : \(5C1=5\)

\(2\) letter words : \(5C2∗2!=10\)

\(3\) letter words : \(5C3∗3!=60\)

\(4\) letter words : \(5C4∗4!=120\)

\(5\) letter words : \(5C5∗5!=120\)

Total \(=5+10+60+120+120=325\)

Ans E

Hope it's clear.
why do we multiply 2! onto 5C2 and all?
User avatar
stne
Joined: 27 May 2012
Last visit: 26 Apr 2026
Posts: 1,811
Own Kudos:
Given Kudos: 681
Posts: 1,811
Kudos: 2,093
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Its_me_aka_ak
stne
Bunuel
Using each letter of the word ZEBRA only once how many one, two, three, four and five-letter words can be created ?

A. 20
B. 60
C. 100
D. 150
E. 325

\(1\) letter words : \(5C1=5\)

\(2\) letter words : \(5C2∗2!=10\)

\(3\) letter words : \(5C3∗3!=60\)

\(4\) letter words : \(5C4∗4!=120\)

\(5\) letter words : \(5C5∗5!=120\)

Total \(=5+10+60+120+120=325\)

Ans E

Hope it's clear.
why do we multiply 2! onto 5C2 and all?

Hi Its_me_aka_ak

5C2 is the number of ways to select 2 things from 5 things.

Note : Doing this does not consider different arrangements of the selected two things.

For e.g. = suppose we have A,B, C, D,E now how many ways to select two things out of 5 things ? This can be done in 5C2 ways. That's 10 ways.

AB
BC
DE
AE
BE
CE
AC
AD
BD
CD

However in the given question since " words" need to be created hence AB and BA will be different words.

But doing 5C2 will not give AB and BA as two different words, it will only one word. To consider all the possibilities we need to multiply by the respective letters in the words.

In this question " Arrangement " also needs to be considered and not only selection.

Hence if we consider AB and BA as two arrangements then in total we will have 20 arrangements.

Hence we multiply by the respective number , because if word consists of two letters then number of ways to arrange them is 2!

If word consists of 3 letters then the number of ways to arrange them is 3!

Basically what we are doing is called permutation.

Hence we multiply by the number of alphabets in the words.

Note this is only in case all the alphabets are distinct, if alphabets are repeated then a different process needs to be followed.

you can visit the permuation and combination topic in gmat club and learn more about this.

Hope it helps.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,988
Own Kudos:
Posts: 38,988
Kudos: 1,118
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109928 posts
Tuck School Moderator
852 posts