Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1912:00 PM PDT
-01:00 PM PDT
Scoring 329 on the GRE is not always about using more books, more courses, or a longer study plan. In this episode of GRE Success Talks, Ashutosh shares his GRE preparation strategy, study plan, and test-day experience, explaining how he kept his prep....
May 2008:00 AM PDT
-08:30 AM PDT
What’s in it for you- Live Profile Evaluation Chat Session with Jenifer Turtschanow, CEO, ARINGO. Come with your details prepared and ARINGO will share insights! Pre-MBA Role/Industry, YOE, Exam Score, C/GPA, ECs Post-MBA Role/ Industry & School List.
May 1501:00 PM IST
-11:00 AM IST
Start your journey with a fully customized action plan and work with a dedicated mentor to achieve a 735+ score.- Jun 10
06:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
21 Jul 2014, 13:38
Kudos
Bookmarks
Can someone please help with this IR problem I got from the Veritas Free Practice Test?
For triangle JKL, angle JKL measures 90 degrees, and side JL has a length of 260 centimeters. If side JK > side KL, which of the following could be a combination of the lengths of sides JK and KL?
50/100/120/200/240
How can I find two sides of the triangle if I only have one?
For triangle JKL, angle JKL measures 90 degrees, and side JL has a length of 260 centimeters. If side JK > side KL, which of the following could be a combination of the lengths of sides JK and KL?
50/100/120/200/240
How can I find two sides of the triangle if I only have one?
erahn1
Joined: 24 Nov 2013
Last visit: 17 Jun 2017
Posts: 21
Given Kudos: 1
Location: United States
Schools: Tuck '17 (D) Carroll '17 (M$)
GMAT 1: 720 Q46 V42
GPA: 3.7
WE:Corporate Finance (Journalism and Publishing)
21 Jul 2014, 18:50
Kudos
Bookmarks
I think the key to this one, and to a lot of IR questions, is to look at the answers afforded to you. If JL is 260, and none of the answers are greater than 260, then JL is surely the hypotenuse.
At this point, and at every point when you are given a right triangle, you should be looking for the three common right triangles, and multiples of those angles,
3 - 4 - 5
5 - 12- 13
8 - 15 - 17
In the problem, 260 is a multiple of 13; 13*20 = 260. So just grab the 5-12-13 triangle, and just multiple each of the other sides by 20; in this case, 20*5 = 100 and 20*12 = 240.
This same approach wouldn't work if you weren't sure that 260 was the hypotenuse, but since it clearly is, I believe the triangle is necessarily a 5-12-13 triangle.
At this point, and at every point when you are given a right triangle, you should be looking for the three common right triangles, and multiples of those angles,
3 - 4 - 5
5 - 12- 13
8 - 15 - 17
In the problem, 260 is a multiple of 13; 13*20 = 260. So just grab the 5-12-13 triangle, and just multiple each of the other sides by 20; in this case, 20*5 = 100 and 20*12 = 240.
This same approach wouldn't work if you weren't sure that 260 was the hypotenuse, but since it clearly is, I believe the triangle is necessarily a 5-12-13 triangle.
