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What is the value of integer \(q\)?
(1) \(qr + qs = r + s\)
(2) \(r\neq{-s}\)
20 Sep 2012, 00:56
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yashii9
Try to follow these steps:
Q(R+S) = 1*(R+S) => Q(R+S) - (R+S) = 0
=>
(Q-1)(R+S)=0
Apply number property here.. This statement (Q-1)(R+S)=0 means
it is possible only if,
case a. Q-1 =0
or
case b. R+S = 0
or
case c. both are 0
We dont have any clue as to which one of these 3 is true.
Now if use statement 2 in question R <> -S which means R+S <> 0, hence if we combine it to the 3 possiblities found in statement 1 : We get choce b is not possible , choice c is not possible. Hence we are left with choice a and Q-1 has to be 0.
So combining the statement gives u ans.. not individual statements.
20 Sep 2012, 01:25
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Good explanation.
However I dont understand how can u solve this as algebra?
point 2 only says that R <> -S but it does not talk abt the value of either r or s.....it can be fraction, positive or zero
unless the values of r and s are specified how do we find value of Q?
Hence E.
I might be thinking a bit too much but its better to get this clarified here than screwing up in the exam.
However I dont understand how can u solve this as algebra?
point 2 only says that R <> -S but it does not talk abt the value of either r or s.....it can be fraction, positive or zero
unless the values of r and s are specified how do we find value of Q?
Hence E.
I might be thinking a bit too much but its better to get this clarified here than screwing up in the exam.
