Last visit was: 03 Aug 2024, 09:08 It is currently 03 Aug 2024, 09:08
Toolkit
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

# Veritas Prep Blog

SORT BY:
Intern
Joined: 16 Aug 2020
Posts: 24
Own Kudos [?]: 10 [0]
Given Kudos: 110
Location: India
GMAT 1: 670 Q48 V34
GPA: 4
WE:Consulting (Computer Software)
Intern
Joined: 16 Aug 2020
Posts: 24
Own Kudos [?]: 10 [0]
Given Kudos: 110
Location: India
GMAT 1: 670 Q48 V34
GPA: 4
WE:Consulting (Computer Software)
Tutor
Joined: 16 Oct 2010
Posts: 15181
Own Kudos [?]: 67091 [0]
Given Kudos: 436
Location: Pune, India
Tutor
Joined: 16 Oct 2010
Posts: 15181
Own Kudos [?]: 67091 [0]
Given Kudos: 436
Location: Pune, India
Karan911 wrote:
VeritasPrepMarisa wrote:
This Blog post was imported into the forum automatically. We hope you found it helpful. Please use the Kudos button if you did, or please PM/DM me if you found it disruptive and I will take care of it. -BB

For the last questions where the entire range is asked for, as per your previous blog I should try bringing the inequality in (x-a) (x-b) <0 form and since we have x^3 (1-4x^2) < 0 here, I didn't do that and got the answer D. I realise my mistake here.
But here's my query:

in the first question we have |-x/3 + 1 | <2,
I got this one right using multiple methods, but if we have |x-a| or |a-x| it doesn't matter here right? We don't need to change |a-x| to |x-a| from by multiplying by -1 and flipping the sign, right?

We don't, right? Because |x-a| = |a-x|.

Yes, |x - a| is equal to |a - x| in all cases.
|a - x| = |-(x - a)| = |x - a| because |-5| = |5|

Take some values for a and x to understand why.
Hence, whenever you see |a - x|, feel free to flip it to |x - a| for your own comfort without the need to modify anything else.
Manager
Joined: 16 Oct 2021
Posts: 140
Own Kudos [?]: 15 [0]
Given Kudos: 22
VeritasPrepMarisa, can you please explain the logic behind multiplying 7C5 by 5! from FROM VERITAS PREP BLOG: WHEN PERMUTATIONS & COMBINATIONS AND DATA SUFFICIENCY COME TOGETHER ON THE GMAT! blog?
Tutor
Joined: 16 Oct 2010
Posts: 15181
Own Kudos [?]: 67091 [1]
Given Kudos: 436
Location: Pune, India