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Updated on: 02 Aug 2012, 04:25
Originally posted by surendar26 on 20 Dec 2010, 10:35.
Last edited by Bunuel on 02 Aug 2012, 04:25, edited 2 times in total.
Last edited by Bunuel on 02 Aug 2012, 04:25, edited 2 times in total.
Edited the question and added the OA
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
76% (01:57) correct
24%
(02:09)
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based on 534
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(429)^2 * 237 * (1243)^3 is thrice of ?
A. 33605 * 31960 * (1243)^2
B. 33654 * 538219 * (1243)^2
C. 33891 * 533247 * (1243)^2
D. 34122 * 532004 * (1243)^2
E. 34606 * 534572 * (1243)^2
A. 33605 * 31960 * (1243)^2
B. 33654 * 538219 * (1243)^2
C. 33891 * 533247 * (1243)^2
D. 34122 * 532004 * (1243)^2
E. 34606 * 534572 * (1243)^2
20 Dec 2010, 13:27
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surendar26
(429)^2*237*(1243)^3 is an odd number.
Among answer choices only C is an odd number, (so thrice C also will be an odd number).
Answer: C.
02 May 2013, 11:59
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arpanpatnaik
\((429)^2\) * 237 * \((1243)^3\)
So we have \((429)^2\) * 237 * \((1243)\) * \((1243)^2\)
the units digit, will be 9^2 = 81 , 237 , 1243 and \((3)^2\) = 9
units digit will be, 1 * 7 * 3 * 9 = 189
Now test the units digit of the answer choices
As \((429)^2\) * 237 * \((1243)^3\) = 3 times of (X),
we are looking for an answer choice that gives the unit digit of 3.
33605 * 31960 * (1243)^2 = 5 * 0 * 9 = 0 (ruled out)
33654 * 538219 * (1243)^2 = 4 * 9 * 9 = 324 (ruled out)
33891 * 533247 * (1243)^2 = 1 * 7 * 9 = 63 ---> thats our answer
34122 * 532004 * (1243)^2 = 2 * 4 * 9 = 72 (ruled out)
34606 * 534572 * (1243)^2 = 6 * 2 * 9 = 108 (ruled out)
