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10 Feb 2011, 12:49
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A Car comes with 7 different possible exterior colors and 6 different interior colors. How many different color combinations are there?
\(A. 26\)
\(B. 42\)
\(C. \frac{7!6!}{2!}\)
\(D. 7!6!\)
\(E. \frac{13!}{2!}\)
\(A. 26\)
\(B. 42\)
\(C. \frac{7!6!}{2!}\)
\(D. 7!6!\)
\(E. \frac{13!}{2!}\)
10 Feb 2011, 12:56
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gmatpapa
For each exterior color out of 7 there are 6 different interior colors possible, so there are total of 7*6=42 color combinations. This is basically the same as Principle of Multiplication: if one event can occur in \(m\) ways and a second can occur independently of the first in \(n\) ways, then the two events can occur in \(mn\) ways.
Answer: B.
