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Acer86
When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 14. Which of the following is true?
(A) 23x + 17y =19
(B) 17x –23y = 9
(C) 17x +23y =19
(D) 14x + 5y = 6
(E) 5x – 14y = -6

Dividend = Divisor*Quotient+Remainder

When the integer n is divided by 17, the quotient is x and the remainder is 5
Dividend=n
Divisor=17
Quotient=x
Remainder=5

n = 17x+5

Likewise;
n is divided by 23, the quotient is y and the remainder is 14
n = 23y+14

\(n=n\)
\(17x+5=23y+14\)
\(17x-23y=9\)

Ans: "B"
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Acer86
Thank you. One

quick question...shouldnt the equation be n/17 = X + 5 ?? why dont we multiply 5 by 17?

Also,
\(\frac{Dividend}{Divisor}=Quotient+\frac{Remainder}{Divisor}\)

\(\frac{n}{17}=x+\frac{5}{17}\)

After multiplying entire equation by 17
\(n=17x+5\)
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n = 17x+5
n = 23y+14

17x+5 = 23y+14 => 17x-23y =9

Answer B.
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n = 17x + 5

n = 23y + 14

So 17x + 5 = 23y + 14

=> 17x –23y = 9


Answer - B
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Dividend Divisor Quotient Remainder
n 17 x 5 n = 17x + 5
n 23 y 14 n = 23y+14

17x + 5 = 23y + 14

On solving, we get option B
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When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 14. Which of the following is true?

(A) 23x + 17y =19
(B) 17x –23y = 9
(C) 17x +23y =19
(D) 14x + 5y = 6
(E) 5x – 14y = -6


n = 17x+5 ------------ (1)
n = 23y+14 ------------(2)

By soving equation (1) & (2),we get the following answer

17x+5=23y+14
ie 17x-23y=9

So.Option (b) is correct.
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Acer86
When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 14. Which of the following is true?

(A) 23x + 17y =19
(B) 17x –23y = 9
(C) 17x +23y =19
(D) 14x + 5y = 6
(E) 5x – 14y = -6
Here's a useful rule:
If A divided by B equals C with remainder D, then it's also true that BC + D = A (this is an important GMAT concept)
Example: Since 32 divided by 5 equals 6 with remainder 2, then it's also true that (5)(6) + 2 = 32

Now onto the question:
We're told that "when n is divided by 17, the quotient is x and the remainder is 5," which means 17x + 5 = n

We're also told that "when n is divided by 23, the quotient is y and the remainder is 14," which means that 23y + 14 = n

Now, if 17x + 5 equals n AND 23y + 14 also equals n, it must be true that 17x + 5 = 23y + 14

If we rearrange the terms of this equation, we get 17x - 23y = 9

Answer: B

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Bunuel
When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 14. Which of the following is true?

(A) 23x + 17y = 19
(B) 17x – 23y = 9
(C) 17x + 23y = 19
(D)14x + 5y = 6
(E) 5x – 14y = -6

"When the integer n is divided by 17, the quotient is x and the remainder is 5"
n = 17x + 5

"When n is divided by 23, the quotient is y and the remainder is 14"
n = 23y + 14

17x + 5 = 23y + 14 = n
17x - 23y = 9

Answer (B)
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Bunuel
When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 14. Which of the following is true?

(A) 23x + 17y = 19
(B) 17x – 23y = 9
(C) 17x + 23y = 19
(D) 14x + 5y = 6
(E) 5x – 14y = -6

When the integer n is divided by 17, the quotient is x and the remainder is 5.
n= 17x + 5

When n is divided by 23, the quotient is y and the remainder is 14
n = 23y +14

On comparing both sides
23y +14 = 17x + 5
17x – 23y = 9

IMO Answer is B.
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Acer86
When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 14. Which of the following is true?

(A) 23x + 17y =19
(B) 17x –23y = 9
(C) 17x +23y =19
(D) 14x + 5y = 6
(E) 5x – 14y = -6

PS66402.01

We see that n/17 = x + 5/17 → n = 17x + 5 and n/23 = y + 14/23 → n = 23y + 14. Therefore, we have:

17x + 5 = 23y + 14

17x - 23y = 9

Answer: B
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n/17 = x + 5
n = 17x + 5

n/23 = y + 14
n = 23y + 14

17x + 5 = 23y + 14
17x - 23y = 9

Answer is B.
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Acer86
When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 14. Which of the following is true?

(A) 23x + 17y =19
(B) 17x –23y = 9
(C) 17x +23y =19
(D) 14x + 5y = 6
(E) 5x – 14y = -6

PS66402.01

\((i) n=17x+5\)

\((ii) n=23y+14\)

Deducting (ii) from (i):


\(0=17x-23y-9\)

\(9=17x-23y\)

\(17x-23y=9\)

The answer is \(B\)
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When the integer n is divided by 17, the quotient is x and the remainder is 5

Theory: Dividend = Divisor*Quotient + Remainder

n -> Dividend
17 -> Divisor
x -> Quotient
5 -> Remainder
=> n = 17*x + 5 = 17x + 5 ..(1)

When n is divided by 23, the quotient is y and remainder is 14

=> n = 23y + 14 ..(2)

From (1) and (2) we get
n = 17x + 5 = 23y + 14

=> 17x - 23y = 14 - 5 = 9

So, Answer will be B
Hope it helps!

Watch the following video to learn the Basics of Remainders

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Acer86
When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 14. Which of the following is true?

(A) 23x + 17y =19
(B) 17x –23y = 9
(C) 17x +23y =19
(D) 14x + 5y = 6
(E) 5x – 14y = -6

PS66402.01
\(17x + 5 = 23y + 14\)

Or, \(17x –23y = 9\), Answer will be (B)
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