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fluke
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least amount of time to finish all 4 steps = > least waiting time between steps.

step1 can start at 7.30
step1/step2 7.30 - 7.45 (15 mins)

wait - (7.45 to 8.00)15 mins

step3 8.00 to 8.20 (20 mins)
wait 10 mins

step4 8.30 to 9.15 (45 mins)

i.e 105 mins = 1hrs 45min

Answer C.
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Regular Cycle
--------------

6:00 AM, 6:30 AM, 7:00 AM,7:30 AM - Mail picked up

6:15 AM, 6:30 AM, 6:45 AM. 7:00 AM, 7:15 AM. 7:30 AM, 7:45 AM - Dropped Off at sorting center

7:00 AM, 8:00 AM, 9:00 AM - Sorted and stamped

7:20 AM, 7:40 AM, 8:00 AM, 8:20 AM, 8:40 AM, 9:00 AM - sent to regional sorting center

8:00 AM, 8:30 AM, 9:00 AM, 9:30 AM - Put in system

9:15 AM, 10:00 AM - Sent to individual carrier

So the least time is when -

7:30 AM - Mail picked up

7:45 AM - Dropped Off at sorting center

8:00 AM - Sorted and stamped

8:30 AM - Put in system

9:15 AM - Sent to individual carrier

1 hr 45 min

Answer - C
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Each step takes 15 + 20 + 45 mint = 1hr 20 min

options D and E are out.

calculating the delays between each steps now

between step 2 and step 3 fixed delay of 15 mint.

Between Step 3 and step 4


step 3 7:00 7:30
process 20min 20min

delay 40 max 10 min

step 4 8:00


thus step3-step4 delay (min) = 10

hence total delay = 15+10 = 25min

adding total = 1:20 min + 25 min = 1:45 mint.

good numerical.
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fluke
At the post office, a letter must go through a sorting process with four distinct steps. Step 1: Mail is picked up every half hour, beginning at 6:00 am. Step 2: Mail is dropped off at the sorting center \frac{1}{4} hour later. Step 3: Mail is sorted by zip code and stamped every 1 hour, beginning at 7:00 am, and sent to regional sorting centers \frac{1}{3} hour later. Step 4: At the regional sorting centers, incoming mail is put into the system every 30 minutes, beginning at 8:00 am, and sent to individual mail carriers 45 minutes later. Assuming that all mail is picked up, sorted, and dropped off on time, what is the least total amount of time that it could take the letter to go through all four steps?


(A) 2 hours 45 minutes

(B) 2 hours 15 minutes

(C) 1 hour 45 minutes

(D) 1 hour 20 minutes

(E) 1 hour 15 minutes

Let's start with step 3 and compare time difference between step 3 and step 4.
Step 3:
[cycle1]
Mail sorting and stamp start time: 7
Mail sent: 7:20
Mail sent: 7:40
[cycle2]
Mail sorted and stamped again: 8
Mail sent: 8:20
Mail sent: 8:40.


Step 4:
[cycle1]
Mail put into system start time: 8
Mail sent: 8:45
[cycle2]
Mail put into system again: 8:30
Mail sent: 9:15

Now check the minimum time between step 3 and step 4.
Sent 7:20 --Put into system at 8. Total time difference= 40minutes
Sent 7:40 --Put into system at 8. Total time difference= 20minutes
Sent 8:20 --Put into system at 8:30. Total time difference= 10minutes
Sent 8:40 --Put into system at 9. Total time difference= 20minutes
Sent 9:20 --Put into system at 9:30. Total time difference= 10minutes

10 minutes is the least time taken between step 3 and step 4. Now pick either 8:20 or 9:20 and work backwards.

Step 3
Mail sorted and stamped again: 8------(1)
Mail sent: 8:20--------(2)
[Time difference between 1 and 2=20]
Step 4--
Mail put into system: 8:30 -------(3)
[Time difference between 2 and 3=10]
Mail sent: 9:15--------(4)
[Time difference between 3 and 4=45]
Step 2
Mail dropped off at 7:45------(5)
[Time difference between 5(mail being dropped off) and 1(mail being sorted and stamped)=15]
Step 1
Mail picked up at 7:30----(6)
[Time difference between 5 and 6=15]

Add all time difference. 15+15+20+10+45= 105minutes = 1hour 45 minutes.

OA C.

Thanks fluke for early morning brain exercise :lol:
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is this a GM math? what source did you find this one????
i found the answer's C too
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Is this a verbal (RC/CR) question or a quant question. I am pretty confused! :-P

That being said, there is no confusion that my answer was wrong. :-D
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At the post office, a letter must go through a sorting process with four distinct steps. Step 1: Mail is picked up every half hour, beginning at 6:00 am. Step 2: Mail is dropped off at the sorting center \(\frac{1}{4}\) hour later. Step 3: Mail is sorted by zip code and stamped every \(1\) hour, beginning at 7:00 am, and sent to regional sorting centers \(\frac{1}{3}\) hour later. Step 4: At the regional sorting centers, incoming mail is put into the system every \(30\) minutes, beginning at 8:00 am, and sent to individual mail carriers \(45\) minutes later. Assuming that all mail is picked up, sorted, and dropped off on time, what is the least total amount of time that it could take the letter to go through all four steps?

(A) \(2\) hours \(45\) minutes
(B) \(2\) hours \(15\) minutes
(C) \(1\) hour \(45\) minutes
(D) \(1\) hour \(20\) minutes
(E) \(1\) hour \(15\) minutes

easy to solve by taking example
- case
step 1-----picked up------7:30
step 2-----delivered-------7:45
step 3-------reach--------7:45-----dispatch 8:00
step 4-------reach--------8:20-----dispatch 8:30
sent----------------------9:15

total time 1:45 Answer
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Mail picked up at 7;30 its confusing
what i got from question is Mail is picked up every half hour, beginning at 6:00 am. so it should be 6;30
plz help me out!
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