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70 = 0,1W + 0,9M
Water = 7 Liter

New1: Add x-Liter water to increase W% from 10% to 25%
New2:
7+x = (70+x)1/4
-42/4 = -3/4x
14 = x

You need to add 14 Liter of Water to get a total of 21 Liter of Water in 84Liter of mixture
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my way
now water is 7/70
it will be (7+X)/(70+X) and it shoud =1/4.
solve and get the answer
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first the amount of water was 70*10%=7

(7+x)/(70+x)=1/4
x=14
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In 70 ltr solution we have 63 ltr of milk and 7 ltr of water
now we are adding water but the amount of milk remains constant so (70+x)*75/100 = 63 where x is the amount of water added
on solving x=14
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I draw the solution for you (attached). It might help you understand it a bit easier.
Attachments

mixture.png
mixture.png [ 25.98 KiB | Viewed 29725 times ]

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(7+x)/(70+x)=1/4
Solve for x; x=14
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Karishma,

I found your post on mixtures very useful. I am stuck in the above problem. Please help
I solved w1/w2 to be
(90-25)/(25-10) = 65/15.

Can you please explain how you got 75/15?
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ENAFEX
Karishma,

I found your post on mixtures very useful. I am stuck in the above problem. Please help
I solved w1/w2 to be
(90-25)/(25-10) = 65/15.

Can you please explain how you got 75/15?

The two mixtures are: a 10% water solution, only water (which is 100% water)
We combine them to get 25% water solution.
Therefore, it is actually (100 - 25)/(25 - 10) and not (90 - 25)/(25 - 10)
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VeritasPrepKarishma, How can we come to know which problems can be solved using the weighted averages formula..Is it applicable to all mixture problems?Or specific ones?
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Ralphcuisak
VeritasPrepKarishma, How can we come to know which problems can be solved using the weighted averages formula..Is it applicable to all mixture problems?Or specific ones?

For most mixture problems, weighted average formula is quite convenient. Whenever you add two things and consider the final solution or have the final solution and split it into two, weighted averages formula is relevant.
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Thank you for the response Karishma..Will look into the article and implement it for mixture problems..
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TomB
In 70 litres of a mixture of milk and water, the quantity of water is 10%. How much water should be added so that new mixture may contain 25%.

A. 10
B. 11
C. 12
D. 13
E. 14

90% of milk means 63 litres will remain the same in the final mix. 63 is the 75% of?

63 * 100/75 = 63 * 4/3 = 21 * 4 = 84

Si the final mix will have 84 litres.

84 - 70 = 14

We need to add 14 litres of water

Posted from my mobile device
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TomB
In 70 litres of a mixture of milk and water, the quantity of water is 10%. How much water should be added so that new mixture may contain 25%.

A. 10
B. 11
C. 12
D. 13
E. 14

I would use Options.

M=63 W=7

Lets add 13 litres of W. We get 20/83. Nope.

Let's add 14 litres of W. We get 21/84=25%. Answer E. (8.4+8.4+4.2=21)
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Answer: Option E

This can be solved quickly using the Weighted Average

\(70 / W = (100 - 25) / (25 - 20)\)

=> \(W = (70 * 15) / 75 = 14 (E)\)
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Can we use Alligation for this question?
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7+X / 70+X = 1/4
70+x = 28 + 4x
42 = 3x
14 = x

Answer is E.
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