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boomtangboy
Joined: 06 Jan 2012
Last visit: 05 Jun 2021
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Status:May The Force Be With Me (D-DAY 15 May 2012)
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Concentration: General Management, Entrepreneurship
Schools: ISB '14 (D) INSEAD Jan '13 (D) Tuck '15 (D) Ross '15 (D) Duke '15 (D) NUS '15 (D) NTU '15 (WL) Ivey '15 (D) Johnson '16 (S)
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28 Apr 2012, 21:43
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C
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81% (01:20) correct
19%
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wrong
based on 666
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The numbers in which of the following pairs do NOT have a pair of distinct prime divisors in common ?
A. 10 and 20
B. 12 and 18
C. 24 and 32
D. 21 and 63
E. 22 and 88
A. 10 and 20
B. 12 and 18
C. 24 and 32
D. 21 and 63
E. 22 and 88
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29 Apr 2012, 04:12
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boomtangboy
There is no need to make prime factorization of all numbers and to check whether they have a pair of distinct prime divisors in common.
32 has only one prime 2 (32=2^5) in its prime factorization, so it can not have a PAIR of distinct prime divisors in common with ANY of the numbers.
Answer: C.
General Discussion
23 Jul 2012, 22:03
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I worked down from A, but Bunuel solution is ingenious.
The problem states...."The numbers in which of the following pairs do NOT have a pair of distinct prime divisors in common ?"
32 only has 2 as a prime factor so clearly not a distinct pair, thus it's automagically
The problem states...."The numbers in which of the following pairs do NOT have a pair of distinct prime divisors in common ?"
32 only has 2 as a prime factor so clearly not a distinct pair, thus it's automagically
