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15 Oct 2012, 19:37
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A
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A certain organization presents reward to some people. There are 3 kinds of reward that respectively are $125, $40, $15. If the total reward is $1,735, what is the least possible value of the number of the people who received reward?
a. 17
b. 22
c. 32
d. 47
e. 90
a. 17
b. 22
c. 32
d. 47
e. 90
11 Dec 2012, 00:11
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To get the minimum value, one must maximize the largest price: $125
\(\frac{1735}{125}=\frac{347}{25}=13rem.110\)
Note that \(13*125=1625\) so we calculate the remaining reward \(40A + 15B = 110\)
Again to get minimum value, maximize the largest remaining reward: \($40\)
\(\frac{110}{40}=2rem.30\)
Note that \(40*2=80\) so we calculate the remaining reward \(15B = 110 - 80 =30\)
\(\frac{30}{15}=2\)
Thus, 13 + 2 + 2 = 17
Answer: A
\(\frac{1735}{125}=\frac{347}{25}=13rem.110\)
Note that \(13*125=1625\) so we calculate the remaining reward \(40A + 15B = 110\)
Again to get minimum value, maximize the largest remaining reward: \($40\)
\(\frac{110}{40}=2rem.30\)
Note that \(40*2=80\) so we calculate the remaining reward \(15B = 110 - 80 =30\)
\(\frac{30}{15}=2\)
Thus, 13 + 2 + 2 = 17
Answer: A
04 Feb 2015, 10:08
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To get the minimum number of people, we want to maximize the number of people receiving the highest award.
1735/125 = 13 remainder 110.
110/40 = 2 remainder 30.
30/15 = 2.
13 +2 +2 = 17.
1735/125 = 13 remainder 110.
110/40 = 2 remainder 30.
30/15 = 2.
13 +2 +2 = 17.
