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Value Substitution works pretty well here.

To make life easy, lets say p = 4 and q = 10.

Then the question becomes: Working at the same constant rate, 4 bricklayers can lay a total of 10 bricks per hour. At this rate, how many bricks could 4 bricklayers lay in 8 hours?

Well if those four can do 10 each hour, then after 8 hours they'll have done 80. So when p = 4 and q = 10, the answer is 80.

Plugging our numbers into the answer choices, we see that only E yields 80.
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megafan
Working at the same constant rate, p bricklayers can lay a total of q bricks per hour. At this rate, how many bricks could 4 bricklayers lay in 8 hours?

(a) \(\frac{p}{2q}\)

(b) \(\frac{2p}{q}\)

(c) \(\frac{32p}{q}\)

(d) \(\frac{2q}{p}\)

(e) \(\frac{32q}{p}\)

We are given that p bricklayers lay a total of q bricks per hour. Thus, the rate for p bricklayers is q. We next need to determine the rate of 4 bricklayers. To determine that rate, we can create a proportion, in which r is the rate for the 4 bricklayers:

p/q = 4/r

pr = 4q

r = 4q/p

Using the formula for work, which is work = rate x time, we see that 4 bricklayers can lay (4q/p) x 8 = 32q/p bricks in 8 hours.

Answer: E
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1) \(pr=\frac{q}{1}; r=\frac{q}{1}*\frac{1}{p}=\frac{q}{p}\)
2) \(4r=\frac{x}{8}; \frac{4q}{p}=\frac{x}{8}; xp=32q; x=\frac{32q}{p}\)
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p bricklayers in 1 hr lay q bricks
Hence 1 bricklayer in 1 hr lays \(\frac{q}{p}\) bricks
Hence 8 bricklayer in 8 hr lay \(\frac{q*8*4}{p}\) bricks i.e., \(\frac{32q}{p}\) bricks .... ANS e
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megafan
Working at the same constant rate, p bricklayers can lay a total of q bricks per hour. At this rate, how many bricks could 4 bricklayers lay in 8 hours?

(a) \(\frac{p}{2q}\)

(b) \(\frac{2p}{q}\)

(c) \(\frac{32p}{q}\)

(d) \(\frac{2q}{p}\)

(e) \(\frac{32q}{p}\)

Source: Gmat Hacks 1800

Variables in the question that are repeated in the answer choices? We can Plug In!!

Let's give ourselves easy numbers...p=4 and q=0.125. How many do they lay in 8 hours? 1 lousy brick.

We can tell by glancing at the answer choices that any with q or 2q in the denominator and p in the numerator are going to be (far) greater than 1.

Answer choice E.


ThatDudeKnowsPluggingIn
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