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25 Oct 2014, 06:12
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
69% (02:01) correct
31%
(02:43)
wrong
based on 104
sessions
History
Date
Time
Result
Not Attempted Yet
In the figure, BD and CD are angular bisectors of <B and <C in an equilateral triangle ABC. What is the ratio of the area polygon ABDC to the area of triangle BDC?
A) 1:2
B) 2:3
C) 3:2
D) 2:1
E) 3:1
A) 1:2
B) 2:3
C) 3:2
D) 2:1
E) 3:1
Attachments
triangle.png [ 6.55 KiB | Viewed 4338 times ]
27 Oct 2014, 21:43
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Join point A to point D
\(\triangle\) ABD = \(\triangle\) ACD = \(\triangle\) BDC
Area polygon ABDC = 2 times Area \(\triangle\) BDC
Ratio = 2:1
Answer = D
\(\triangle\) ABD = \(\triangle\) ACD = \(\triangle\) BDC
Area polygon ABDC = 2 times Area \(\triangle\) BDC
Ratio = 2:1
Answer = D
Attachments
triangle.png [ 2.29 KiB | Viewed 4219 times ]
