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Bunuel
In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course?

A. 6
B. 15
C. 24
D. 33
E. 54

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Total=French+German-Both+Neither
78=41+22-9+Neither
Neither=78-54
Neither=24

Answer: C
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Total = F+G+neither-both
78=41+22-9+neither; therefore neither=24

Hence answer is C


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Using the set formula :
A'U'B - ~(A'U'B) = A + B - AB
need to find ~(A'U'B) = x, say.
78 - x = 41 + 22 - 9
=> x = 24.
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Bunuel
In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course?

A. 6
B. 15
C. 24
D. 33
E. 54

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OFFICIAL SOLUTION:

You could solve this by drawing a Venn diagram. A simpler way is to realize that you can subtract the number of students taking both languages from the numbers taking French to find the number taking only French. Likewise find those taking only German. Then we have:Total = only French + only German + both + neither
78 = (41-9) + (22-9) + 9 + neither.

Not enrolled students = 24.

Answer: C.
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You could even do this way as well
P(F) = 41/78
P(G) = 22/78
P(FNG) = 9/78

1 - P(FUG) = 41/78 + 22/78 - 9/78
1- P(FUG) = 54/78
P(FUG) = 1 - 54/78
P(FUG) = 24/78

Therefore, answer is C
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Bunuel
In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course?

A. 6
B. 15
C. 24
D. 33
E. 54

[Note: Here we are assuming that every student learns either Physics or Chemistry or both.]

Let’s let b = the number of students learning both Physics and Chemistry. Let’s also assume that there are 100 students. Since 70% of the students learn Physics and 65% of the students learn Chemistry, we could say that:

100 = 65 + 70 - b

100 = 135 - b

b = 35

Answer: C
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I got to the answer in 21 seconds with quick mental math.

41 French + 22 German = 63
63 F&G - 9 in both = 54 in foreign language classes.
78-54 ends in a 4 and narrows my answer choices to 24 or 54. I know easily that 54+54 is too big so I’m left with only 24, C, as my option

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Since 9 are taking both courses,

Only French = 41 - 9 =32

Only German = 22 - 9 =13

Total = Only French + Only German + Both + Neither

=> 78 = 32 + 13 + 9 + Neither

=> Neither = 78 - 54 = 24

Alternately,

Total=French + German -Both +Neither

=>78=41+22-9+Neither

=>Neither=78-54 = 24

(option c)

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