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A&&B = b^(1/2) -a. What is the value of p in 16&&p = 9 ? 15 Apr 2015, 04:12
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E
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25% (medium)

Question Stats:

70% (00:57) correct 30% (00:59) wrong based on 352 sessions

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A&&B = \(\sqrt{b} -a\). What is the value of p in 16&&p = 9 ?

(A) -5
(B) 9
(C) 13
(D) 25
(E) 625


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E
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A&&B = b^(1/2) -a. What is the value of p in 16&&p = 9 ? 15 Apr 2015, 04:17
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Bunuel
A&&B = \(\sqrt{b} -a\). What is the value of p in 16&&p = 9 ?

(A) -5
(B) 9
(C) 13
(D) 25
(E) 625


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if A&&B = \(\sqrt{b} -a\) and 16&&p = 9 then p=625
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A&&B = b^(1/2) -a. What is the value of p in 16&&p = 9 ? 15 Apr 2015, 08:29
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Bunuel
A&&B = \(\sqrt{b} -a\). What is the value of p in 16&&p = 9 ?

(A) -5
(B) 9
(C) 13
(D) 25
(E) 625


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\(\sqrt{p}\)-16=9
\(\sqrt{p}\)=25
p=625

Answer: E
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A&&B = b^(1/2) -a. What is the value of p in 16&&p = 9 ? 15 Apr 2015, 08:35
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Bunuel
A&&B = \(\sqrt{b} -a\). What is the value of p in 16&&p = 9 ?

(A) -5
(B) 9
(C) 13
(D) 25
(E) 625


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16&&p=9
\sqrt{p}-16=9
\sqrt{p}\sqrt{}=25
p=625
Answer E
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A&&B = b^(1/2) -a. What is the value of p in 16&&p = 9 ? 15 Apr 2015, 13:10
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'\sqrt{p}' - 16 = 9
'\sqrt{p}' = 25
p = 25^2 = 625
Answer E
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A&&B = b^(1/2) -a. What is the value of p in 16&&p = 9 ? 15 Apr 2015, 14:43
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16 && p = 9
=> \(\sqrt{p}\) -16 = 9
=> \(\sqrt{p}\) = 25
=>p =\(25^2\)= 625

Answer E
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A&&B = b^(1/2) -a. What is the value of p in 16&&p = 9 ? 16 Apr 2015, 08:56
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since A&&B =√b−a, and 16&&p=9, then

√p−16=9; √p=25;p=625
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A&&B = b^(1/2) -a. What is the value of p in 16&&p = 9 ? 20 Apr 2015, 06:20
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Bunuel
A&&B = \(\sqrt{b} -a\). What is the value of p in 16&&p = 9 ?

(A) -5
(B) 9
(C) 13
(D) 25
(E) 625


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MAGOOSH OFFICIAL SOLUTION

Be careful not to fall the trap that switches the order of b and a. Our equation should read: \(\sqrt{p} - 16 = 9\). Solving for p:

\(\sqrt{p} = 25\)
p = 625.

Answer (E).
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A&&B = b^(1/2) -a. What is the value of p in 16&&p = 9 ? 08 May 2021, 07:34
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