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Situation is something like the picture depicts. So the belt which is 10 ft long will go around both the semi-circles (wheels) which are of the same dia.

So semicircular circumference *2 + distance between the centres*2 = 10

pi*1/4*2 + 2*d = 10

2d = 10-pi/2

d = (20-pi)/4

Answer is B
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467a8e3c121d5e88baaacfee253dcdb0_conveyor-belt-by-porletto-conveyor-belts-clipart_1024-366-2.jpeg
467a8e3c121d5e88baaacfee253dcdb0_conveyor-belt-by-porletto-conveyor-belts-clipart_1024-366-2.jpeg [ 37.72 KiB | Viewed 2357 times ]

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naeln
A mechanic wants to join the motor wheel to the pump wheel with a thin belt. Both wheels have an equal diameter of 1/2 feet. If his belt is only 10 feet long, until how far, in feet, can he position the pump wheel’s center from the motor wheel’s center?
a. \(\frac{10 - pi}{2}\)
b. \(\frac{20-pi}{4}\)
c. \(\frac{20pi}{4}\)
d. 10 - pi
e. 20

(10-1/2*⫪)/2=(20-⫪)/4
B
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gracie
naeln
A mechanic wants to join the motor wheel to the pump wheel with a thin belt. Both wheels have an equal diameter of 1/2 feet. If his belt is only 10 feet long, until how far, in feet, can he position the pump wheel’s center from the motor wheel’s center?
a. \(\frac{10 - pi}{2}\)
b. \(\frac{20-pi}{4}\)
c. \(\frac{20pi}{4}\)
d. 10 - pi
e. 20

(10-1/2*⫪)/2=(20-⫪)/4
B

Given that \(d_1\)=\(d_2\)=\(d\)=1/2
Please refer the diagram as well.
Hence , \(d_1\)*⫪/2 =\(d_2\)*⫪/2 =\(d\)*⫪/2
Hence according to the question \(2x\)+\(2\)*\(d\)*⫪/2 =\(10\)
or \(2x\)+\(2\)*(1/2)*⫪/2 =\(10\)
or \(2x\)+⫪/2 =\(10\)
or \(4x\)+⫪=20
or \(4x\)=20 -⫪
or \(x\)=(20 -⫪)/4.................Hence option B.
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