Jack has two dice, one has six equally probable sides, labeled 1, 2, 3

Question

Jack has two dice, one has six equally probable sides, labeled 1, 2, 3, 4, 5, 6, and the other has seven equally probable sides, labeled 1, 2, 3, 4, 5, 6, 7. If Jack rolls both dice what is the probability that both of the numbers will be odd?

A. 3/14
B. 2/7
C. 1/3
D. 1/2
E. 12/21

Kudos for a correct solution.

A. 3/14
B. 2/7
C. 1/3
D. 1/2
E. 12/21

Kudos for a correct  solution .

GMATinsight · Answer

METHOD-1

Probability that the number on first die is odd = 3/6  
Probability that the number on Second die is odd = 4/7

Probability that Both Dice result in odd numbers = (3/6)*(4/7) = 2/7

Answer: Option B

METHOD-2

Probability that the number on first die is odd = 3/6  
Probability that the number on Second die is odd = 4/7

Probability that the number on first die is odd and second is even = (3/6)*(3/7)
Probability that the number on Second die is odd and First is even = (3/6)*(4/7)
Probability that the number on Both dice is even = (3/6)*(3/7)

Favourable Probability = 1- Unfavourable Probability

i.e. Favourable Probability = 1-   = 1 -   = 1 -   = 1 - (5/7) = 2/7

Answer: Option B

ENGRTOMBA2018 · Answer

Porbability = Total number of acceptable cases / Total number of all the cases

In this case, total number of all the cases = 6*7 = 42

'Acceptable cases' = 
1,1
1,3
1,5
1,7
Similarly with 3 and 5 for a total of = 3*4 = 12

Thus, the required probability = 12/42 = 2/7. Thus B is the correct answer.

TimeTraveller · Answer

D1 = {1,2,3,4,5,6}; D2 = {1,2,3,4,5,6,7}

Sample Space = 6*7 = 42.

Odd Numbers: in D1 = {1,3,5}; in D2 = {1,3,5,7}

Favourable Events = {1,1}, {1,3}, {1,5}, {1,7}, {3,1}, {3,3}, {3,5}, {3,7}, {5,1}, {5,3}, {5,5}, {5,7}, {7,1}, {7,3}, {7,5} = 12 events.

Probability = 12/42 = 2/7. (B).

EMPOWERgmatRichC · Answer

Hi All,

This question is a fairly standard probability question, so figuring out the individual probabilities and multiplying them together is a great approach for this prompt (and if you're not comfortable with that math yet, FireStorm's 'brute force' approach to list out all the possibilities is ALSO great).

The answer choices are 'spaced out' enough that you can still get the correct answer with a bit of logic, but you do have to understand fraction-to-decimals conversions and the basic math/logic behind rolling standard dice.

Since a standard 6-sided die has 3 odd 'sides' and 3 even 'sides', the probability of rolling an odd number on a single die is 1/2. By extension, the odds of rolling two odd numbers on two dice is (1/2)(1/2) = 1/4. Here though, the second die is a 7-sided die and a little MORE than half of the numbers are odd (4/7 to be precise, but it's enough to say a 'little more than half'), so rolling a 6-sided die and a 7-sided die gives us a probability of getting two odds that is a little MORE than 1/4....

There's only one answer that's a little more than 1/4...

Final Answer:  B

GMAT assassins aren't born, they're made,
Rich

Bunuel · Answer

800score Official Solution:

(B) For the first die there are 6 possible numbers, for the second die there are 7 possible numbers. When both are rolled together there are (6)(7) = 42 possible combinations. On the first die there are 3 odd numbers and on the second die there are 4 odd numbers. There are (3)(4) = 12 possible combinations where both numbers are odd. The probability that both numbers will be odd is 12/42 = 2/7.

TheGmatTutor · Answer

I think the 800Score official solution is too complex.

I'd just take the individual probabilities of rolling an odd number, and multiply them.

1/2 * 4/7 = 4/14 = 2/7

Answer: B

100mitra · Answer

Correct Option : B 
Given : 
Jack has Two dice
- D1 - {1, 2, 3, 4, 5, 6} Total 6 Number | Odd Number {1,3,5} 
- D2 - {1, 2, 3, 4, 5, 6, 7} -Total 7 Number | Odd Number {1,3,5,7} 
To Find : Probability - both of the numbers will be odd
P(D1) x P(D2) = (3/6) x (4/7) = 12/42 =  (2/7)

bumpbot · Answer

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Jack has two dice, one has six equally probable sides, labeled 1, 2, 3

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