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Difficulty:
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(low)
Question Stats:
89%
(01:48)
correct 11%
(02:43)
wrong
based on 85
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History
Date
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In a 40-mile trip, the first 20 miles were traveled in 50mph. If the total trip average speed is 60mph, what should be the average speed in the last 20 miles?
A) 150 B) 75 C) 50 D) 45 E) 40
This question dos not apear to be difficult, but it took me too much time to solve. Does anyone has a fast way of killing it?
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In a 40-mile trip, the first 20 miles were traveled in 50mph. If the total trip average speed is 60mph, what should be the average speed in the last 20 miles?
A) 150 B) 75 C) 50 D) 45 E) 40
This question dos not apear to be difficult, but it took me too much time to solve. Does anyone has a fast way of killing it?
As far as your question is concerned, the simplest way is to observe that the distance of 20 miles is half of 40 miles. Thus treating this as a simple average problem , we can see that for 2 things to have an average of 60 with 1 being 50, the other needs to be just more than 60 to bring the average up to 60. Thus B is the only logical answer. Option A will give you a comparatively higher average value while rest of the options will decrease the average.
The above method was applicable only because the speeds given were exactly at mid way of the total distance. Had it been at any other point (2/3rds of the total distance etc) then we would have to apply the average speed formula.
In a 40-mile trip, the first 20 miles were traveled in 50mph. If the total trip average speed is 60mph, what should be the average speed in the last 20 miles?
A) 150 B) 75 C) 50 D) 45 E) 40
This question dos not apear to be difficult, but it took me too much time to solve. Does anyone has a fast way of killing it?
Show more
METHOD-1
Time = Distance / Speed
Time to travel First 20 miles = 20/50 = 2/5 hours
Total Time to cover 40 miles = 40/60 = 2/3 hours
i.e. Time to cover last 20 miles = (2/3)-(2/5) = 4/15 hours
Speed = Distance / Time
Speed while covering last 20 miles = 20/(4/15) = 75
METHOD-2
Average speed for equal to and fro motion = 2ab / (a+b) where a and b are speeds in to and fro cases
60 = 2*50*b/(50+b)
i.e. b = 75
Answer: Option B
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