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22 Jul 2015, 02:09
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
85% (01:39) correct
15%
(01:36)
wrong
based on 191
sessions
History
Date
Time
Result
Not Attempted Yet
8, 19, 30, 41, 52, ….
Given the sequence above, what is the sum of the 10th and the 20th terms?
A. 324
B. 335
C. 346
D. 357
E. 368
Kudos for a correct solution.
Given the sequence above, what is the sum of the 10th and the 20th terms?
A. 324
B. 335
C. 346
D. 357
E. 368
Kudos for a correct solution.
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Given Kudos: 816
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
22 Jul 2015, 04:16
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Bunuel
GIven sequence = 8,19,30,41,52....
Thus \(S_n = S_{n-1} + 11\)
\(S_{10} = S_1+(10-1)*11 = 8+9*11\)
\(S_{20} = S_1+(20-1)*11= 8+19*11\)
Thus the sum = 8+9*11+ 8+19*11 = 16+11(20+8) = 16+220+88 = 220+104 = 324. A is the correct answer.
22 Jul 2015, 04:41
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8, 19, 30, 41, 52, ...
a = 8, d = 11.
10th term = a+9d = 8+9*11 = 107
20th term = a+21d = 8+19*11 = 217
sum = 107+217 = 324. Ans (A).
a = 8, d = 11.
10th term = a+9d = 8+9*11 = 107
20th term = a+21d = 8+19*11 = 217
sum = 107+217 = 324. Ans (A).
