Last visit was: 23 Apr 2026, 21:36 It is currently 23 Apr 2026, 21:36
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,785
Own Kudos:
810,886
 [7]
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,785
Kudos: 810,886
 [7]
Kudos
Add Kudos
7
Bookmarks
Bookmark this Post
User avatar
balamoon
Joined: 26 Dec 2011
Last visit: 04 May 2025
Posts: 111
Own Kudos:
313
 [3]
Given Kudos: 91
Schools: HBS '18 IIMA
Schools: HBS '18 IIMA
Posts: 111
Kudos: 313
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Own Kudos:
3,890
 [2]
Given Kudos: 816
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
GMAT 1: 750 Q49 V44
Posts: 2,319
Kudos: 3,890
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Own Kudos:
3,890
 [2]
Given Kudos: 816
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
GMAT 1: 750 Q49 V44
Posts: 2,319
Kudos: 3,890
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
balamoon
Bunuel
There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability that the both positions will be taken by members of just one party?

A. 1/25
B. 12/49
C. 1/4
D. 24/49
E. 1/2

Kudos for a correct solution.

Solution -

There are 25 democrats and 25 republicans.

The probability that the both positions will be taken by democrats or republicans = (25C2 +25C2)/50C2 = 300/1225 = 12/49. ANS B.

The text marked in red above is not calculated correctly. It should be 24/49 and not 12/49.

(25C2 + 25C2)/50C2 = 600/1225 = 24/49
User avatar
TimeTraveller
Joined: 28 Jun 2015
Last visit: 29 Jul 2017
Posts: 237
Own Kudos:
361
 [1]
Given Kudos: 47
Concentration: Finance
GPA: 3.5
Posts: 237
Kudos: 361
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Probability that both positions will be taken by Democrats = 25C2/50C2 = 600/2450 = 12/49.
Probability that both positions will be taken by Republicans = 25C2/50C2 = 600/2450 = 12/49.

Required probability = 12+12/49 = 24/49. Ans (D).
avatar
LaxAvenger
Joined: 18 Aug 2014
Last visit: 10 Nov 2017
Posts: 91
Own Kudos:
Given Kudos: 36
Location: Hong Kong
Schools: Mannheim
Schools: Mannheim
Posts: 91
Kudos: 159
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability that the both positions will be taken by members of just one party?

A. 1/25
B. 12/49
C. 1/4
D. 24/49
E. 1/2

Kudos for a correct solution.


(25C2 + 25C2) / 50C2 = 24/49. Answer D

But I always wonder.. how can we find out which way to choose: Combinatorics as I just did or:

(2/25 * 1/24) * 2 ... why will this one give us an incorrect result.?. it is quite hard for me to understand ...
avatar
kasinowr
Joined: 08 Jun 2015
Last visit: 26 Jul 2015
Posts: 3
Own Kudos:
6
 [2]
Given Kudos: 21
GPA: 3.9
Posts: 3
Kudos: 6
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
alternative solution that doesnt involve large numbers:

probability of one party having both spots:

(1/2) * (24/49) = 12/49

(1/2) or (25/50) because it does not matter which party or which person gets the first spot. (24/49) because after one person from a particular party is chosen, there are 24 members of the same party left out of 49 total candidates.

Since this result can happen for both parties, (12/49) + (12/49) = (24/49)

Answer: D
User avatar
JJo
Joined: 08 Jul 2012
Last visit: 24 Oct 2016
Posts: 42
Own Kudos:
103
 [1]
Given Kudos: 15
Posts: 42
Kudos: 103
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability that the both positions will be taken by members of just one party?

A. 1/25
B. 12/49
C. 1/4
D. 24/49
E. 1/2

Kudos for a correct solution.

We can select 2 members of one particular type:
25/1 * 24/2 * 2

We can select 2 members of any type:
50/1 * 49/2

P(both positions will be taken by members of just one party) = 25*24*2 / 50*49 = 24/49

Ans. D. 24/49
User avatar
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Own Kudos:
Given Kudos: 816
Concentration: Finance, Strategy
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
GMAT 1: 750 Q49 V44
Posts: 2,319
Kudos: 3,890
Kudos
Add Kudos
Bookmarks
Bookmark this Post
LaxAvenger
Bunuel
There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability that the both positions will be taken by members of just one party?

A. 1/25
B. 12/49
C. 1/4
D. 24/49
E. 1/2

Kudos for a correct solution.


(25C2 + 25C2) / 50C2 = 24/49. Answer D

But I always wonder.. how can we find out which way to choose: Combinatorics as I just did or:

(2/25 * 1/24) * 2 ... why will this one give us an incorrect result.?. it is quite hard for me to understand ...


The text in red is incorrect. How are you able to write the total combinations/ways as : 1/25 or even 1/24 (how can the total ways be fractions?)? Can you show some steps by which you got these numbers?
User avatar
EMPOWERgmatRichC
User avatar
Major Poster
Joined: 19 Dec 2014
Last visit: 31 Dec 2023
Posts: 21,777
Own Kudos:
13,047
 [1]
Given Kudos: 450
Status:GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Expert
Expert reply
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Posts: 21,777
Kudos: 13,047
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi All,

In these types of questions, there are usually several different ways to do the 'math' involved. It's important to be on the lookout for any conceptual 'shortcuts' that are built into the question though - the GMAT rarely requires that you perform a really complex calculation to get to the solution.

Here, we're told that there are 25 Democrats and 25 Republicans. We're asked for the probability that two elected positions will go to the SAME party.

Since the calculation 'hinges' on the party of the second person elected matching the party of the first person elected, the first person COULD come from EITHER party (in math terms, the first person elected does NOT matter - the issue is "does the second person come from the same party as the first person?").

Once 1 Democrat OR 1 Republican is elected, there will be only 24 members of that party remaining (and 49 total people remaining. Thus, the probability that the second person comes from the same party as the first is...

24/49

Final Answer:
GMAT assassins aren't born, they're made,
Rich
User avatar
KS15
Joined: 21 May 2013
Last visit: 25 Jul 2019
Posts: 531
Own Kudos:
Given Kudos: 608
Posts: 531
Kudos: 259
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability that the both positions will be taken by members of just one party?

A. 1/25
B. 12/49
C. 1/4
D. 24/49
E. 1/2

Kudos for a correct solution.
Both candidates will either be Democrats or Repub.

Required probability= (25C2+25C2)/50C2=600/25*49=24/49
Answer D
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,785
Own Kudos:
810,886
 [1]
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,785
Kudos: 810,886
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability that the both positions will be taken by members of just one party?

A. 1/25
B. 12/49
C. 1/4
D. 24/49
E. 1/2

Kudos for a correct solution.

800score Official Solution:

Let’s consider an outcome to be an ordered pair (x, y), where x is a member, who took position #1, y is a member, who took position #2. There are 50 × 49 possible outcomes.

There are 25 × 24 favorable outcomes for one party (x and y are from the same party). So there are 2 × (25 × 24) favorable outcomes in total.

The probability is (2 × 25 × 24) / (50 × 49) = 24/49.

The correct answer is D.
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,963
Own Kudos:
Posts: 38,963
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109784 posts
Tuck School Moderator
853 posts