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sahil7389
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sahil7389
Each of the four children has a bag with five different colored discs in it; red blue green yellow and orange. If each child in succession randomly chooses exactly one disc from his bag to flip into a hat. What is the probability that hat will no hold no repeated colours at the end flipping?


A- 1/5
B- 6/625
C- 24/625
D- 24/125
E- 6/125

Either OA given by 800score is wrong or my understanding is wrong. Cos my answer is D.

Total Outcomes = 5*5*5*5 = 5^4 [Because every child has 5 ways to choose one disc from his/her bag]

Favourable Outcomes = 5C4*4!
[5C4 are the ways to select 4 colours out of 5 colours for discs
and
4! are the ways to arrange the different coloured discs among 4 children]


i.e. Favourable Outcomes = 5C4*4!= 5*24 = 120

Probability = 120/5^4 = 24/125

Answer: option D
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sahil7389
Each of the four children has a bag with five different colored discs in it; red blue green yellow and orange. If each child in succession randomly chooses exactly one disc from his bag to flip into a hat. What is the probability that hat will no hold no repeated colours at the end flipping?


A- 1/5
B- 6/625
C- 24/625
D- 24/125
E- 6/125

Either OA given by 800score is wrong or my understanding is wrong. Cos my answer is D.
EDIT---OA edited as per Gmat Insight Answer.

The first child can flip a disc of any color into the hat; thus, his probability is 5/5 = 1. The second child can flip a disc of any color other than the color the first child has already flipped; thus, his probability is 4/5. Using the same analogy, the probability of the third child is 3/5 and that of the fourth child is 2/5. Therefore, the overall probability is 1 x 4/5 x 3/5 x 2/5 = 24/125.

Answer: D
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