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Bunuel
If each curved portion of the boundary of the figure above is formed from the circumference of two semicircles, each with a radius of 2, and each of the parallel sides has length 4, what is the area of the shaded figure?

A. 16
B. 32
C. \(16-8\pi\)
D. \(32-8\pi\)
E. \(32-4\pi\)

Ans: B
Solution: If we shift these semicircle, which are out ward dense, to the blank space of the same size in between parallel lines we will get one big rectangle. so practically we need to find the area of the rectangle only.

which is 8x4= 32 [Ans]
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i thought the figure will form a rectangle when we stretch the sheet
But length will be 4 and breath will be combined circumference of two circle=2pir=4pi.
Please explain again with diagram.
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i thought the figure will form a rectangle when we stretch the sheet
But length will be 4 and breath will be combined circumference of two circle=2pir=4pi.
Please explain again with diagram.

Refer to if-each-curved-portion-of-the-boundary-of-the-figure-attached-is-forme-203894.html#p1562850
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Bunuel

If each curved portion of the boundary of the figure above is formed from the circumference of two semicircles, each with a radius of 2, and each of the parallel sides has length 4, what is the area of the shaded figure?

A. 16
B. 32
C. \(16-8\pi\)
D. \(32-8\pi\)
E. \(32-4\pi\)

Attachment:
Kaplan.png

Hi chetan2u,

Two semi circles circumference makes one whole circle circumference. So basically in this question we have to find the surface area of a cylinder with a height of 4 cms and radius 2 cms

so \(2*\pi *2\) *4 = \(16\pi\)
what's wrong with this logic ? Why is this not leading to the answer?
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Bunuel

If each curved portion of the boundary of the figure above is formed from the circumference of two semicircles, each with a radius of 2, and each of the parallel sides has length 4, what is the area of the shaded figure?

A. 16
B. 32
C. \(16-8\pi\)
D. \(32-8\pi\)
E. \(32-4\pi\)

Attachment:
Kaplan.png

Hi chetan2u,

Two semi circles circumference makes one whole circle circumference. So basically in this question we have to find the surface area of a cylinder with a height of 4 cms and radius 2 cms

so \(2*\pi *2\) *4 = \(16\pi\)
what's wrong with this logic ? Why is this not leading to the answer?

You are going wrong because you are taking it as a 3-d figure whereas it is just a 2-dimensional figure or a figure on a page..
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* Each of the parallel side as 4 cm- For which the given figure above will be a square.

Area of square = 16
Area of 2 circle with radius 2 = 8pi^2

Area of shaded portion - 16- 8pi

(All Area in sq.cm and radius in cm)

Please let me know my mistake in solving the problem
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