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14 Sep 2015, 22:12
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:35) correct
27%
(01:46)
wrong
based on 252
sessions
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In a card game, a combination of two aces beats all others. If Jose is the first to draw from a standard deck of 52 cards, what is the probability that he wins the game with the best possible combination?
A) 1/221
B) 13/221
C) 2/52
D) 3/51
E) 4/51
Source : Sandeep Gupta Quant
A) 1/221
B) 13/221
C) 2/52
D) 3/51
E) 4/51
Source : Sandeep Gupta Quant
15 Sep 2015, 04:54
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Sharan.0516
The best possible combination is the case when he wins in his first two draws
There are 52 cards in a deck of cards with 4 aces in it.
Probability of first card to be ace = 4/52
Probability of Second card to be ace = 3/51
Probability of Best possible case = (4/52)*(3/51) = 1/221
P.S. The language of this question ("Best possible combination") is not the Language that GMAT uses in the questions.
Answer: Option A
IdiomSavant
Joined: 14 Sep 2016
Last visit: 03 May 2018
Posts: 45
Given Kudos: 119
Concentration: Finance, Economics
Schools: Boston U '20 Carroll '20
24 Jan 2017, 09:10
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"In a card game, a combination of two aces beats all others. If Jose is the first to draw from a standard deck of 52 cards, what is the probability that he wins the game with the best possible combination?"
I agree with the approach and the answer.
The question itself is ambiguous.
Someone else could have 2 aces since there are four aces; the question doesn't state whether Jose still wins if he draws.
I agree with the approach and the answer.
The question itself is ambiguous.
Someone else could have 2 aces since there are four aces; the question doesn't state whether Jose still wins if he draws.
