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Bunuel
Jerry’s average (arithmetic mean) score on the first 3 of 4 tests is 85. If Jerry wants to raise his average by 2 points, what score must he earn on the fourth test?

A. 87
B. 89
C. 90
D. 93
E. 95

Total score on 3 tests = 85*3 = 255
Jerry wants the average to be = 87
Hence total score on 4 tests should be = 87*4 = 348

Score required on the fourth test = 348 - 255 = 93
Option D
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Bunuel
Jerry’s average (arithmetic mean) score on the first 3 of 4 tests is 85. If Jerry wants to raise his average by 2 points, what score must he earn on the fourth test?

A. 87
B. 89
C. 90
D. 93
E. 95

No need for any calculations. The final average Jerry wants - 87.

Another way average can be visualised when one says the average of 4 tests is 87, is to think that Jerry got 87 in all 4 tests.

To get 87 in all 4, he needs 2 points in the previous 3 tests, and also 87 in the final one. So that means only if Jerry gets (87+2*3)=93 in the final test, can we re-distribute those 2 points across each of the previous 3 tests and end up with 87 in each exam.

D.
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85*3 +S = 87 *4
s=93

Ans: D
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