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03 Jan 2016, 13:32
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97% (01:08) correct
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In the figure above, if BC = CD and angle ADC = 90 degrees, then what is the value of x?
A. 45
B. 50
C. 70
D. 75
E. 100
Attachment:
2016-01-04_0031.png [ 6.39 KiB | Viewed 5892 times ]
03 Jan 2016, 20:30
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[quote="Bunuel"]
In the figure above, if BC = CD and angle ADC = 90 degrees, then what is the value of x?
angle BDC also = 70
90-70=20
angle ABD=180-70=110
180-110-20
=50
B. 50
In the figure above, if BC = CD and angle ADC = 90 degrees, then what is the value of x?
angle BDC also = 70
90-70=20
angle ABD=180-70=110
180-110-20
=50
B. 50
04 Jan 2016, 00:29
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Slightly longer method:
1. CBD = 70
2. Due to the isosceles triangle angle rules, BDC = 70
3. BCD = 180 - 70 - 70
4. BCD = 40
5. BAD (angle x) = 180 - 90 (due to right triangle) - 40
6. BAD (angle x) = 50
The answer is B, x = 50.
1. CBD = 70
2. Due to the isosceles triangle angle rules, BDC = 70
3. BCD = 180 - 70 - 70
4. BCD = 40
5. BAD (angle x) = 180 - 90 (due to right triangle) - 40
6. BAD (angle x) = 50
The answer is B, x = 50.
