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paisaj87
Joined: 06 Jan 2015
Last visit: 30 Jan 2017
Posts: 48
Given Kudos: 7
Schools: Insead Sept '17 (A) HEC Dec"18 (A)
08 Feb 2016, 08:54
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
75% (02:31) correct
25%
(03:13)
wrong
based on 242
sessions
History
Date
Time
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Not Attempted Yet
Nails and screws are manufactured at a uniform weight per nail and a uniform weight per screw. If the total weight of one screw and one nail is half that of 6 screws and one nail, then the total weight of 3 screws, and 3 nails is how many times that of 4 screws and 2 nails?
a. 4
b. 5/2
c. 2
d. 3/2
e. 5/4
a. 4
b. 5/2
c. 2
d. 3/2
e. 5/4
08 Feb 2016, 09:02
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paisaj87
Hi,
let the weight of nail be n and that of screw be s..
so s+w=1/2 * (6s+1n)...
or 1n = 4s..
lets see the weight of 3 s and 3n= 3s+3*4s=15s..
and weight of 4s and 2n= 4s+2*4s=12s..
ratio= 15s/12s=15/12=5/4
E
19 May 2020, 09:17
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paisaj87
\(s + n = \frac{6s + n}{2}\)
So, \(2s + 2n = 6s + n\)
Or, \(n = 4s\)
Now, we have to find -
Quote:
Or, 3s + 3n = 3s + 3(4s) => 15s
And, 4s + 2n = 4s + 2(4d) => 12s
Hence required fraction is 15/12 = 5/4, Answer must be (E)
