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Bunuel
Sue has only pennies, dimes, and nickels in a jar. The jar has at least 1 but no more than 4 pennies. If the jar has at least 1 nickel and 1 dime, which of the following could NOT be the total amount of money in the jar?

A. 51 cents
B. 53 cents
C. 55 cents
D. 57 cents
E. 59 cents

For a Non US citizen like me i dunno how to approach this question . No idea whats a Nickle ,dime or a penny. Do we need to remember this conversion?
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Bunuel
Sue has only pennies, dimes, and nickels in a jar. The jar has at least 1 but no more than 4 pennies. If the jar has at least 1 nickel and 1 dime, which of the following could NOT be the total amount of money in the jar?

A. 51 cents
B. 53 cents
C. 55 cents
D. 57 cents
E. 59 cents

For a Non US citizen like me i dunno how to approach this question . No idea whats a Nickle ,dime or a penny. Do we need to remember this conversion?

Penny = 1 cent, nickel = 5 cents, dime = 10 cents.

The question itself will supply the relative conversions such as this one. Though you should have a few basic ones memorized: 1 hour = 60 minutes, ...

Check other Conversion problems to practice in Special Questions Directory.
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My approach:

Total money value = (1 x P) + (5 x N) + (10 x D) = P + 5(N+2D) so Total - P = 5(N+2D)
where P, N, D are numbers of penny, nickel, and dimes respectively.

Form the question, P =1,2,3, or 4

So Total - P must be divisible by 5
Check if the answer can minus any of the values of P mentioned above to have a multiple of 5:

A. 51 -1 = 50.
B. 53 - 3 = 50.
C. 55 can't make any multiple of 3 with P. Stop here, this is the answer.
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NamVu1990
My approach:

Total money value = (1 x P) + (5 x N) + (10 x D) = P + 5(N+2D) so Total - P = 5(N+2D)
where P, N, D are numbers of penny, nickel, and dimes respectively.

Form the question, P =1,2,3, or 4

So Total - P must be divisible by 5
Check if the answer can minus any of the values of P mentioned above to have a multiple of 5:

A. 51 -1 = 50.
B. 53 - 3 = 50.
C. 55 can't make any multiple of 3 with P. Stop here, this is the answer.

Thanks! This is a great way to solve this problem.



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