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Bunuel
If x and y are integers and √x−√y equals an odd integer, which of the following must be an even integer?

I. xy
II. x^2 + y^2
III. x/y

A. I only
B. I and II
C. II​ only
D. I, II, and III
E. None of these

\(\sqrt{x} - \sqrt{y}\) = Odd number

So, X or Y can be Even / Odd; however both can not be even.

Check using properties of Number system

I. xy

Product of an Odd and Even Number must always be Even Number

II. x^2 + y^2

Square of an Odd number is Odd Number and Square of an even number is even Number
Further Odd + Even Number = Odd Number


III. \(\frac{x}{y}\)

Now, x / y can be even / odd

If x is even and y odd then \(\frac{x}{y}\) is even

However if x is odd and y even then \(\frac{x}{y}\) is odd


Thus using property of Number system we can find that option (A) is correct !! :-D :lol:
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Exponent does not affect the even/odd nature of x,y

Hence x-y=odd
so xy is even
x^2+y^2 is odd
And x/y may or may not be an integer

So A
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Option A

x & y are integers such that \(\sqrt{x} - \sqrt{y}\) = Odd Integer
Hence, x & y must perfect squares AND \(\sqrt{x}\) & \(\sqrt{y}\) must be either Odd & Even or Even & Odd.

I. xy = E
II. x^2 + y^2 = E^2 + O^2 or O^2 + E^2 = E + O or O + E = O
III. x/y = E/O or O/E = E or O or F
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