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Bunuel
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If n is a prime number between 0 and 100, how many positive divisors 20 Apr 2016, 01:03
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68% (00:57) correct 32% (00:55) wrong based on 323 sessions

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If \(n \) is a prime number between 0 and 100, how many positive divisors does \(n^3\) have?

A. 1
B. 2
C. 3
D. 4
E. 5
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D
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If n is a prime number between 0 and 100, how many positive divisors 20 Apr 2016, 02:51
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mathiaskeul
I'd say the answer is 1 because every divisor is just a multiple of the original prime?
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Hi,
we are basically looking at factors of\(n^3,\) where n is a PRIME number..
number of factors \(= (3+1) = 4.\).
we can also write them down.
1, n, \(n^2\), and \(n^3\)
so ans will be 4
D
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If n is a prime number between 0 and 100, how many positive divisors 20 Apr 2016, 02:37
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I'd say the answer is 1 because every divisor is just a multiple of the original prime?
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If n is a prime number between 0 and 100, how many positive divisors 20 Apr 2016, 02:57
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chetan2u
mathiaskeul
I'd say the answer is 1 because every divisor is just a multiple of the original prime?


Hi,
we are basically looking it factors of\(n^3,\) where n is a PRIME number..
number of factors \(= (3+1) = 4.\).
we can also write them down.
1, n, \(n^2\), and \(n^3\)
so ans will be 4
D
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Hi chetan. Could you explain the rule for this? Is it only for prime numbers?

Thank you!
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If n is a prime number between 0 and 100, how many positive divisors 20 Apr 2016, 03:03
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mathiaskeul
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mathiaskeul
I'd say the answer is 1 because every divisor is just a multiple of the original prime?


Hi,
we are basically looking it factors of\(n^3,\) where n is a PRIME number..
number of factors \(= (3+1) = 4.\).
we can also write them down.
1, n, \(n^2\), and \(n^3\)
so ans will be 4
D

Hi chetan. Could you explain the rule for this? Is it only for prime numbers?

Thank you!
Show more

Hi,

when ever you are looking for the number of factors/positive divisors, get the integer in its simplest form/scientific notation ..
for example say 36..
\(36 = 2^2*3^2\).. ans will be (2+1)(2+1) = 3*3=9..
\(120 = 2^3*3*5\).. ans will be (3+1)(1+1)(1+1) = 4*2*2=16..

say a Q further asks you ODD factor of 120..
just drop the even 2-- (3+1)(1+1)(1+1) .. ans will be (1+1)(1+1)=2*2=4..
Even factors will be Total - ODD = 16-4=12..
May help somewhere
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If n is a prime number between 0 and 100, how many positive divisors 20 Apr 2016, 03:05
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mathiaskeul
chetan2u
mathiaskeul
I'd say the answer is 1 because every divisor is just a multiple of the original prime?


Hi,
we are basically looking it factors of\(n^3,\) where n is a PRIME number..
number of factors \(= (3+1) = 4.\).
we can also write them down.
1, n, \(n^2\), and \(n^3\)
so ans will be 4
D

Hi chetan. Could you explain the rule for this? Is it only for prime numbers?

Thank you!
Show more

Finding the Number of Factors of an Integer:

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.

Check for more here: math-number-theory-88376.html
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If n is a prime number between 0 and 100, how many positive divisors 20 Apr 2016, 13:45
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Two ways to solve this one
Pick has 2 => 8 has 4 factors hence D
next way to solve this up is using the formula => if K=P^a * Q^b * R^c where P,Q,R are primes ; then the number of divisors of K are => a+1 * b+1 * c+1


Hit that D option .
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If n is a prime number between 0 and 100, how many positive divisors 02 Jul 2018, 10:02
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Bunuel
If n is a prime number between 0 and 100, how many positive divisors does n^3 have?

A. 1
B. 2
C. 3
D. 4
E. 5
Show more

If let n = 2, then n^3 = 8, which has divisors of 1, 2, 4, and 8, so n^3 has 4 positive divisors. This concept holds for any prime number n^3. It is always/only divisible by 1, n, n^2, and n^3.

Answer: D
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If n is a prime number between 0 and 100, how many positive divisors 15 Jun 2022, 07:44
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Since we know that n is a prime number, and the formula for finding the number of factors for any number N is
N = a^x X b^y....., where a and b are the prime factors
number of factors = (x+1)X(y+1).

Therefore for this question the answer would be (3+1) = 4
Option D

+Kudos, if this explanation helps
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If n is a prime number between 0 and 100, how many positive divisors 14 Jan 2024, 11:52
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