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29 Apr 2016, 20:16
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
52% (01:15) correct
48%
(01:31)
wrong
based on 391
sessions
History
Date
Time
Result
Not Attempted Yet
There are different 10 circles. What is the number of the greatest possible points with which the circles intersect?
A. 90
B. 100
C. 110
D. 180
E. 200
* A solution will be posted in two days.
A. 90
B. 100
C. 110
D. 180
E. 200
* A solution will be posted in two days.
29 Apr 2016, 20:38
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Maximum points of intersection between n different circles = n*(n - 1) = 10*9 = 90
Answer: A
Similar question from Math Revolution: what-is-the-greatest-possible-number-of-points-at-which-11-circles-210362.html
Answer: A
Similar question from Math Revolution: what-is-the-greatest-possible-number-of-points-at-which-11-circles-210362.html
29 Apr 2016, 20:49
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MathRevolution
Hi,
if someone is not aware of the formula, you can easily do the Q through systematic approach..
VISUALIZATION can help us in these type of Qs,
first circle - no intersection
second circle - 2-points
third circle- two existing circles s0 2*2 - 4..
and so on till 10th - 9 existing circle and 2-points on each = 2*9=18..
\(TOTAL = 0+2+4+...16+18 = 2(1+2+3+...8+9) = 2*9*\frac{10}{2} = 90\)
A
