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06 Jun 2016, 04:37
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
94% (00:36) correct
6%
(01:14)
wrong
based on 206
sessions
History
Date
Time
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Not Attempted Yet
A right triangle is inscribed in a circle. The legs of the triangle have lengths 6 and 8. What is the diameter of the circle?
(A) 8
(B) \(8\pi\)
(C) \(9\sqrt 3\)
(D) 10
(E) 12
(A) 8
(B) \(8\pi\)
(C) \(9\sqrt 3\)
(D) 10
(E) 12
06 Jun 2016, 05:58
Kudos
Bookmarks
diameter = hypotenuse =h
h^2 = 6^2+8^2 = 36+64=100
h=10
h^2 = 6^2+8^2 = 36+64=100
h=10
06 Jun 2016, 07:43
Kudos
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If right triangle is inscribed in a circle, its hypothenuse will always be the diameter of the circle.
If we know that 2 legs of that right triangle are 6 & 8, then we can easily find the hypothenuse (diameter of the circle) by using the Pythagorean theorem.
\(d^2 = 6^2 + 8^2 = 100\)
d = 10
Answer: D
If we know that 2 legs of that right triangle are 6 & 8, then we can easily find the hypothenuse (diameter of the circle) by using the Pythagorean theorem.
\(d^2 = 6^2 + 8^2 = 100\)
d = 10
Answer: D
