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Bunuel
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E-16

2C1*4C2 + 2C2* 4C1 =12+4 =16

very easy method
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We have 2 women = 2 W, and 4 men = 4M

We want to select 3 people from these 2W and 4M, with at least 1 W

So we can have : WMM or WWM, but no more women since there are only 2.

WMM = 1 from 2 * 2 from 4 = 12
WWM = 2 from 2 * 1 from 4 = 4

So, 12 + 4 = 16
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Solution

s

Given
    • Group of two women and four men.

To find
    • Committee of three people such that at least one member must be a woman.

Approach and Working out
Total number of ways of selecting three people out of 4 men and 2 women = \(6C_3\) = 20.
The number of ways of selecting three people with no woman = \(4C_3\) = 4.

Thus, the number of ways of selecting 3 people out of two groups such that at least one woman is selected = 20 = 4 = 16.

Correct Answer: Option E
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