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A+B = 4 --- (Statement 1)
B+C =9---- (Statement 2)
C+D =3--- (Statement 3)

From statement 2 and 3

B-D =6 --- (Statement 4)

Subtract statement 4 from 2


A +D = -2 .. hence answer : E
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Bunuel
If (A+B) = 4, (B+C) = 9 and (C+D) = 3, what is the value of (A+D)?

A. 16.
B. 8.
C. 7.
D. 2.
E. -2.

subtract B+C from A+B
A-C=-5
add to this one C+D
A+D=-2.
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Answer is -2. Easy one, but I screw up this kind of questions when I take actual CATs :-/


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A + B = 4
B + C = 9
C + D = 3
-----------

Adding all 3 equation

A + 2B + 2 C + D = 4 + 9 + 3
==> A + 2(B+C) + D = 16

==> A+D = 16 - 2 * 9 = -2
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A+B=4
B+C=9
C+D=3

A+B=4
B=4-A

C+D=3
D=3-D

B+C=9
(4-A)+(3-D)=9
7-A-D=9
-A-D=2
-1(-A-D=2)
A+D=-2
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Bunuel
If (A+B) = 4, (B+C) = 9 and (C+D) = 3, what is the value of (A+D)?

A. 16.
B. 8.
C. 7.
D. 2.
E. -2.
Write all the equations, one under another, with variables B and C aligned

Multiply the second equation (B + C) by (-1), note the signs, and add all three.

A + B = 4
___-B - C = -9
______+C + D = +3
---------------------------
A . . . .+ D = -2

Answer E
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