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Bunuel
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Three different lumberjacks can chop W amount of wood in 30 minutes, 4 22 Aug 2016, 03:02
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Three different lumberjacks can chop W amount of wood in 30 minutes, 45 minutes, and 50 minutes according to their different levels of skill with the axe. How much wood, in terms of W, could the two fastest lumberjacks chop in 2 hours?

A. \(6 \frac{2}{3} W\)

B. 6 W

C. \(4 \frac{2}{3} W\)

D. 3 W

E. \(2 \frac{2}{3} W\)
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A
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Three different lumberjacks can chop W amount of wood in 30 minutes, 4 22 Aug 2016, 06:59
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Bunuel
Three different lumberjacks can chop W amount of wood in 30 minutes, 45 minutes, and 50 minutes according to their different levels of skill with the axe. How much wood, in terms of W, could the two fastest lumberjacks chop in 2 hours?

A. \(6 \frac{2}{3} W\)

B. 6 W

C. \(4 \frac{2}{3} W\)

D. 3 W

E. \(2 \frac{2}{3} W\)
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The two fastest lumberjacks are the 30 mins and 45 mins ones.
The 30 mins guy can complete W in 30 mins and so in 2 hours he can complete W * 120/30 = 4W amount
The 45 mins guy can complete W in 45 mins and so in 2 hours he can complete W * 120/45 = \(2 \frac{2}{3} W\)

These 2 combined will complete in 2 hours = 4W + \(2 \frac{2}{3} W\) = \(6 \frac{2}{3} W\) .
Answer is A
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Three different lumberjacks can chop W amount of wood in 30 minutes, 4 22 Aug 2016, 07:47
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Bunuel
Three different lumberjacks can chop W amount of wood in 30 minutes, 45 minutes, and 50 minutes according to their different levels of skill with the axe. How much wood, in terms of W, could the two fastest lumberjacks chop in 2 hours?

A. \(6 \frac{2}{3} W\)

B. 6 W

C. \(4 \frac{2}{3} W\)

D. 3 W

E. \(2 \frac{2}{3} W\)
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We know that W = RT and we are asked to find the value in terms of W then we can take R = W/T form.

Since 30,45 and 50 given respectively, the first two are the fastest among the three.(R1,R2 and R3)..here 2 hours can be taken as 120 minutes..

W = R1(30) then in 120 we get W = R1(30/120) => W= R1(1/4) => 4W = R1

W = R2(45) then in 120 mins we get W = R2(45/120) => W = R2(9/24) => 24/9(W) = R2..

Now we are asked to find the rate of two fastest = R1 + R2 = 4W + 24/9(W) = 60/9(W)..... IMO Option A is the correct answer...

OA please...will correct if I missed anything..
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Three different lumberjacks can chop W amount of wood in 30 minutes, 4 23 Aug 2016, 05:59
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Lumberjack who complete 1 unit of work (1W) in complete in 30 mins => In 1 hour he will complete 2 unit of work (2W)

Lumberjack who complete 1 unit of work (1W) in complete in 45 mins (45/60 = 3/4 hr) => In 1 hr he will complete 4W/3 = 1.33 units of work

Lumberjack who complete 1 unit of work (1W) in complete in 50 mins (50/60 = 5/6 hr) => In 1 hr he will complete 6W/5 = 1.2 units of work

Two fastest lumberjacks -> who complete more amount of work in a hr -> Lumberjacks who completed work in 30 mins and 45 mins resp.

Together in 1 hr, 2 fastest lumberjacks will complete --> 2W + (4W/3) = 10W/3 work

Hence, in 2 hrs, they will do 2 * (10W/3) = 20W/3 --> 6.66 Work ---> Option A.
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Three different lumberjacks can chop W amount of wood in 30 minutes, 4 23 Aug 2016, 08:42
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Bunuel
Three different lumberjacks can chop W amount of wood in 30 minutes, 45 minutes, and 50 minutes according to their different levels of skill with the axe. How much wood, in terms of W, could the two fastest lumberjacks chop in 2 hours?

A. \(6 \frac{2}{3} W\)

B. 6 W

C. \(4 \frac{2}{3} W\)

D. 3 W

E. \(2 \frac{2}{3} W\)
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A = time taken to chop 1 wood by A
B = time taken to chop 1 wood by B

Since (1/A)*(30/60) = W
Therefore 1/A = 2W

(1/B)*(45/60) = W
Therefore 1/B = 4W/3

(1/A+1/B)*2 = x (amount of wood to be chopped in 2 hours)
= [2W + 4W/3]*2 = 20W/3
Answer = A
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Three different lumberjacks can chop W amount of wood in 30 minutes, 4 23 Aug 2016, 13:19
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Bunuel
Three different lumberjacks can chop W amount of wood in 30 minutes, 45 minutes, and 50 minutes according to their different levels of skill with the axe. How much wood, in terms of W, could the two fastest lumberjacks chop in 2 hours?

A. \(6 \frac{2}{3} W\)

B. 6 W

C. \(4 \frac{2}{3} W\)

D. 3 W

E. \(2 \frac{2}{3} W\)
Show more

Let's say the W amount of work done = 1, and we know that the two fastest lumberjacks (say x and y) can chop the wood in 30minutes ( = 1/2 hr) and 45 minutes (= 3/4 hr).

work rate * time = amount of work ===> (W/x + W/y) * 2 = (1/x + 1/y) * 2 = [1/(1/2) + 1/(3/4)] * 2 = (2/1 + 4/3) * 2 = 10/3 * 2 = 20/3 = 6 2/3

So answer is A
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Three different lumberjacks can chop W amount of wood in 30 minutes, 4 03 Jun 2017, 13:01
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Bunuel
Three different lumberjacks can chop W amount of wood in 30 minutes, 45 minutes, and 50 minutes according to their different levels of skill with the axe. How much wood, in terms of W, could the two fastest lumberjacks chop in 2 hours?

A. \(6 \frac{2}{3} W\)

B. 6 W

C. \(4 \frac{2}{3} W\)

D. 3 W

E. \(2 \frac{2}{3} W\)
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2 fastest lumberjacks are 30 min one and 45 minute one. In 2 hours, 30 minute one can chop 4, while 45 minute one can do >2. Only A is greater than 6. Answer is A
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Three different lumberjacks can chop W amount of wood in 30 minutes, 4 20 Jun 2025, 03:09
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