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22 Aug 2016, 03:02
Kudos
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A
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Three different lumberjacks can chop W amount of wood in 30 minutes, 45 minutes, and 50 minutes according to their different levels of skill with the axe. How much wood, in terms of W, could the two fastest lumberjacks chop in 2 hours?
A. \(6 \frac{2}{3} W\)
B. 6 W
C. \(4 \frac{2}{3} W\)
D. 3 W
E. \(2 \frac{2}{3} W\)
A. \(6 \frac{2}{3} W\)
B. 6 W
C. \(4 \frac{2}{3} W\)
D. 3 W
E. \(2 \frac{2}{3} W\)
Senthil1981
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22 Aug 2016, 06:59
Kudos
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Bunuel
Three different lumberjacks can chop W amount of wood in 30 minutes, 45 minutes, and 50 minutes according to their different levels of skill with the axe. How much wood, in terms of W, could the two fastest lumberjacks chop in 2 hours?
A. \(6 \frac{2}{3} W\)
B. 6 W
C. \(4 \frac{2}{3} W\)
D. 3 W
E. \(2 \frac{2}{3} W\)
A. \(6 \frac{2}{3} W\)
B. 6 W
C. \(4 \frac{2}{3} W\)
D. 3 W
E. \(2 \frac{2}{3} W\)
The two fastest lumberjacks are the 30 mins and 45 mins ones.
The 30 mins guy can complete W in 30 mins and so in 2 hours he can complete W * 120/30 = 4W amount
The 45 mins guy can complete W in 45 mins and so in 2 hours he can complete W * 120/45 = \(2 \frac{2}{3} W\)
These 2 combined will complete in 2 hours = 4W + \(2 \frac{2}{3} W\) = \(6 \frac{2}{3} W\) .
Answer is A
+1 for kudos
22 Aug 2016, 07:47
Kudos
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Bunuel
Three different lumberjacks can chop W amount of wood in 30 minutes, 45 minutes, and 50 minutes according to their different levels of skill with the axe. How much wood, in terms of W, could the two fastest lumberjacks chop in 2 hours?
A. \(6 \frac{2}{3} W\)
B. 6 W
C. \(4 \frac{2}{3} W\)
D. 3 W
E. \(2 \frac{2}{3} W\)
A. \(6 \frac{2}{3} W\)
B. 6 W
C. \(4 \frac{2}{3} W\)
D. 3 W
E. \(2 \frac{2}{3} W\)
We know that W = RT and we are asked to find the value in terms of W then we can take R = W/T form.
Since 30,45 and 50 given respectively, the first two are the fastest among the three.(R1,R2 and R3)..here 2 hours can be taken as 120 minutes..
W = R1(30) then in 120 we get W = R1(30/120) => W= R1(1/4) => 4W = R1
W = R2(45) then in 120 mins we get W = R2(45/120) => W = R2(9/24) => 24/9(W) = R2..
Now we are asked to find the rate of two fastest = R1 + R2 = 4W + 24/9(W) = 60/9(W)..... IMO Option A is the correct answer...
OA please...will correct if I missed anything..
