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PawanRamnani1234
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In the rectangular coordinate system above, the area of parallelogram Updated on: 04 Jan 2023, 07:16
Originally posted by PawanRamnani1234 on 06 Sep 2016, 20:01.
Last edited by Bunuel on 04 Jan 2023, 07:16, edited 2 times in total.
Renamed the topic and edited the question.
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69% (02:09) correct 31% (02:43) wrong based on 332 sessions

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In the rectangular coordinate system above, the area of parallelogram KLMN is :-

A. \(\frac{6}{\sqrt 3}\)
B. 6
C. \(6\sqrt3\)
D. 12
E. Cannot be determined.

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B
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atturhari
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In the rectangular coordinate system above, the area of parallelogram 06 Sep 2016, 20:17
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Distance between K & L = 2 - 0 (x co-ordinates) = 2.

Since KL and MN are parallel, b is 3 (y o-ordinates on the same line).

Area = l * h = 2 * 3 = 6
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OreoShake
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In the rectangular coordinate system above, the area of parallelogram 16 Oct 2016, 07:28
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If we try to solve this by equating the slopes for NK and ML, we get a as -2. -2 does not give a positive value for X coordinate for M (3a-2). Can someone please help resolve this?

Thank you.
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In the rectangular coordinate system above, the area of parallelogram 24 Oct 2016, 12:53
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PawanRamnani1234
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The attachment IMG_20160907_082651.jpg is no longer available
In the rectangular coordinate system above, the area of parallelogram KLMN is :-

a) \(\frac{6}{\sqrt 3}\)
b) 6
c) \(6\sqrt3\)
d) 12
e) cannot be determined.
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Area of parallelogram=B*H
B(base)= KL=MN
from co ordinates K&L ---->KL=2
H(height)=line perpendicular to X axis from point K or Point L
from L(2,3)---->height =3

thus area = 2*3=6

Ans B
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LeonidK
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In the rectangular coordinate system above, the area of parallelogram 05 Mar 2017, 02:54
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KL parallel to NM and KL = NM
KN parallel to LM and KN = LM

KL = 2
LM = 3

Area = KL * LM = 2 * 3 = 6
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Nunuboy1994
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In the rectangular coordinate system above, the area of parallelogram 16 Jun 2017, 22:31
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PawanRamnani1234
Attachment:
IMG_20160907_082651.jpg
In the rectangular coordinate system above, the area of parallelogram KLMN is :-

a) \(\frac{6}{\sqrt 3}\)
b) 6
c) \(6\sqrt3\)
d) 12
e) cannot be determined.
Show more

The diagram is an optical illusion meant to test your knowledge of the properties of a paralleogram- the two must must be parallel so b must have the same y value as the coordinate adjacent to it.


Thus
"B"
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In the rectangular coordinate system above, the area of parallelogram 16 Jun 2017, 23:52
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PawanRamnani1234
Attachment:
IMG_20160907_082651.jpg
In the rectangular coordinate system above, the area of parallelogram KLMN is :-

a) \(\frac{6}{\sqrt 3}\)
b) 6
c) \(6\sqrt3\)
d) 12
e) cannot be determined.
Show more


From the diagram we can see that one side of parallelogram lies on x-axis
so parallel side must have same y coordinate
-> b = 3
Also distance on the bottom side = distance on parallel side
(3a-2)-(2a-2) = (2-0)
a = 2

So area = base x height = 3 x 2 = 6
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In the rectangular coordinate system above, the area of parallelogram 19 Mar 2021, 23:39
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Opposite sides of a parallelogram are equal and parallel.

Since the 1 upper/left vertex has an X coordinate of 0 and the opposite side is the X Axis———-> the length of the Upper Side parallel to the X axis = (2) - (0) = 2

Using this as the Base of the parallelogram, the Height will be given by the perpendicular distance between the 2 parallel sides (1 of which is on the X Axis)

Therefore, the Height perpendicular to the X Axis and Bottom side of the parallelogram is equal to the Y Coordinate of (2 , 3)

Height = 3


Area of parallelogram = (base) * (height) = (2) (3) = 6

(B)

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In the rectangular coordinate system above, the area of parallelogram 05 Mar 2023, 09:39
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