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Updated on: 08 Sep 2016, 07:05
Originally posted by PawanRamnani1234 on 08 Sep 2016, 06:54.
Last edited by Bunuel on 08 Sep 2016, 07:05, edited 1 time in total.
Last edited by Bunuel on 08 Sep 2016, 07:05, edited 1 time in total.
Renamed the topic and edited the question.
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
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Question Stats:
69% (02:15) correct
31%
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wrong
based on 637
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What is the area inscribed by the lines y =1, x = 1, y = 6-x on an xy-coordinate plane?
a) 8
b) 10
c) 12
d) 14
e) 18
a) 8
b) 10
c) 12
d) 14
e) 18
Updated on: 15 Jul 2020, 11:43
Originally posted by BrushMyQuant on 08 Sep 2016, 07:11.
Last edited by BrushMyQuant on 15 Jul 2020, 11:43, edited 1 time in total.
Last edited by BrushMyQuant on 15 Jul 2020, 11:43, edited 1 time in total.
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Check the attached image
We are supposed to find the area of the figure enclosed by the lines x=1, y=1 and y=6-x which is nothing but Area of Triangle ABC.
AB = 4 (distance between (1,1) and (5,1))
AC = 4 (distance between (1,1) and (1,5))
Area of Triangle ABC which is right angled at A = (1/2) * AB * AC = (1/2)*4*4 = 8
So, Answer A
Hope it helps!
We are supposed to find the area of the figure enclosed by the lines x=1, y=1 and y=6-x which is nothing but Area of Triangle ABC.
AB = 4 (distance between (1,1) and (5,1))
AC = 4 (distance between (1,1) and (1,5))
Area of Triangle ABC which is right angled at A = (1/2) * AB * AC = (1/2)*4*4 = 8
So, Answer A
Hope it helps!
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Updated on: 22 Feb 2021, 06:36
Originally posted by BrentGMATPrepNow on 08 Sep 2016, 08:04.
Last edited by BrentGMATPrepNow on 22 Feb 2021, 06:36, edited 2 times in total.
Last edited by BrentGMATPrepNow on 22 Feb 2021, 06:36, edited 2 times in total.
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PawanRamnani1234
First, let's graph the lines y = 1 and x = 1
At this point, we need to find the points where the line y = 6-x INTERSECTS the other two lines.
For the vertical line, we know that x = 1, so we'll PLUG x = 1 into the equation y = 6-x to get y = 6-1 = 5
Perfect, when x = 1, y = 5, so one point of intersection is (1,5)
For the horizontal line, we know that y = 1, so we'll PLUG y = 1 into the equation y = 6-x to get 1 = 6-x. Solve to get: x = 5
So, when y = 1, x = 5, so one point of intersection is (5,1)
Now add these points to our graph and sketch the line y = 5-x
At this point, we can see that we have the following triangle.
The base has length 4 and the height is 4
Area = (1/2)(base)(height)
= (1/2)(4)(4)
= 8
Answer:
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