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|--7mts--|--7mts--|..............

He places a fence after each post. I.e he builds 99 fences before putting down the 100th post.
99*7
Units digit is 3. No need to calculate. Answer is B
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alanforde800Maximus
A farmer constructs a fence along the northern edge of his property, using materials such
that he places a post every 7 meters. if he uses 100 posts, how many meters will the fence span?

a)686
b)693
c)700
d)707
e)770

Please assist with above problem.
I like the solutions above. I literally drew a picture.

For any specific range with "marked off" beginning and end values, there will always be one more tick than interval.

Wasn't sure I remembered that rule correctly, so I drew 10 posts, and wrote 7 in between:

|7|7|7|7|7|7|7|7|7|

Then I counted. 10 fence posts, but only 9 lengths of 7 in between. So 100 fence posts = 99 intervals of 7 meters.

99*7 = 693. Answer B
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Hi All,

This is an example of a 'fence post' problem (literally and figuratively). The 'key' to these types of questions is to remember that there's a 'first post' that you have to include in your total. Here's a much simpler example of this type of math - if you read pages 2 through 5 (inclusive) of a book, then how many pages did you read? It's 4 pages (not 3), since you read pages 2, 3, 4 and 5.

Thus, we have the first post, then another post every 7 meters. That means that we're 99(7) meters away from the first post once we plant the last post.

(99)(7) = 693

Final Answer:

GMAT assassins aren't born, they're made,
Rich
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We can also use the formula for arithmetic progression!

\(ntn = a + d (n -1)\)

nth = The value we are looking for.

a = 0 mts
d = 7 mts (every 7 meters)
n = 100 posts

\(nth = 0 + 7 (100 -1)\)

\(nth = 693\)
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Nanobotstv
A farmer constructs a fence along the northern edge of his property, using materials such that he places a post every 7 meters. if he uses 100 posts, how many meters will the fence span?

A. 686
B. 693
C. 700
D. 707
E. 770

Alternately, we can also use the formula to find the \(n^{th}\) term of an arithmetic progression i.e. first term + (n - 1) * common difference

Here, the posts are separated with a fixed distance of \(7\) meters hence common difference is \(7\) meters. The first post is at \(0\) meters hence we need find the location of the \(100^{th}\) post

\(0 + (100 - 1) * 7 = 99 * 7 = 693\)

Ans. B
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