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Bunuel
If 16^x/4^y = 64, which of the following must be true?

A. 4x+6=2y
B. 2x−y=6
C. y−2x=3
D. y=2x−3
E. 2y−x=3

\(\frac{16^x}{4^y} = 64\)

Or, \(\frac{2^{4x}}{2^{2y}} = 2^6\)

Or, \(2^{ 4x - 2y } = 2^6\)

Or, \(4x - 2y = 6\)

Or, \(2x - y = 3\)

Or, \(y = 2x - 3\)

Answer will be (D) \(y = 2x - 3\)
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Bunuel
If 16^x/4^y = 64, which of the following must be true?

A. 4x+6=2y
B. 2x−y=6
C. y−2x=3
D. y=2x−3
E. 2y−x=3


Let’s simplify each component of the given equation:

16^x = 2^4x

4^y = 2^2y

64 = 2^6

So we have:

(2^4x)/(2^2y) = 2^6

2^(4x - 2y) = 2^6

4x - 2y = 6

4x - 6 = 2y

y = 2x - 3

Answer: D
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Bunuel
If 16^x/4^y = 64, which of the following must be true?

A. 4x+6=2y
B. 2x−y=6
C. y−2x=3
D. y=2x−3
E. 2y−x=3


it's given ,

\(16^x\)/\(4^y\) =64

\(([m]4^2\))^x[/m] / \(4^y\) = \(4^3\)

\(4^{2x}\)/\(4^Y\)= 4^3
\(4^{2x-y}\) = \(4^3\)
2x-y =3
y = 2x -3

Thus the best answer is D.
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I feel the questions should use brackets, i understood that the / is in the power of the digit
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Ujjwal98
I feel the questions should use brackets, i understood that the / is in the power of the digit

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