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There are 11 letters. Two are fixed G and T. You are left with 9 letters. If all 9 were different then answer would have been 9!

There are 2 I. Then answer is 9!/2! ( once T is fixed at first or last, middle T can be treated as new one)

Suppose G and T can be fixed at first or last then it will be 9! / 2! X 2
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First and last letters G & T are fixed. Only I is repeated in remaining 9 letters. Therefore, 9!/2!


philipssonicare
Explanation needed please!
I got 2·9! 2 Gs, 2 Ts and 9!/2! arrangements for the others

Posted from my mobile device
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In how many ways can the letters of a word 'G M A T I N S I G H T' be arranged to form different words such that each word starts with a "G" and ends with a "T" (whether the word makes sense or not)?

A) 11!
B) 9!
C) 8!
D) 9!/2!
E) 11!/(2!*2!*2!)

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G M A T I N S I G H T

Total Letters = 11

T used twice
I used twice
G used once
M used once
A used once
N used once
S used once
G used once
H used once

Gis fixed at first place and T is fixed at last place so the letters to be arranged = 11-2 = 9

Among those 9 letters there is one letter I repeated twice

Therefore total arrangements of 9 letters = 9!
the arrangements repeated due to swapping of identical letter 'I' = 2!

i.e. total desired outcomes = 9! / 2!

Answer: Option D

I hope this helps!!!

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GMATinsight
In how many ways can the letters of a word 'G M A T I N S I G H T' be arranged to form different words such that each word starts with a "G" and ends with a "T" (whether the word makes sense or not)?

A) 11!
B) 9!
C) 8!
D) 9!/2!
E) 11!/(2!*2!*2!)

Source: https://www.GMATinsight.com

Will use LOMO (lines, options, multiply, order) method here.

G M A T I N S I G H T

So after fixing G and T at the first place and the last place respectively, we have 9 lines i.e. we have to arrange 9 letter internally

That can be done in 9! ways.

Now in the nine letter I appears twice.
Does the order in which both I's can be written matters?
No, since I's are identical.

So we will divide the result by the no. of ways two I's can be arranged internally i.e. 2!

Hence the answer will be \(\frac{9!}{2!}\)

Answer is (D)
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