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Updated on: 12 Mar 2017, 18:46
Originally posted by MathRevolution on 09 Mar 2017, 02:42.
Last edited by MathRevolution on 12 Mar 2017, 18:46, edited 1 time in total.
Last edited by MathRevolution on 12 Mar 2017, 18:46, edited 1 time in total.
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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63% (01:46) correct
37%
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In the x-y plane, what is the slope between y-intercept and a negative x-intercept of \(y=x^2+x-6\)?
A. -2
B. -3
C. 2
D. 4
E. 6
A. -2
B. -3
C. 2
D. 4
E. 6
09 Mar 2017, 03:40
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y = x^2 +x -6
for y intercept, x = 0. Putting the value we get y=-6. hence the co-ordinate = (0,-6)
For the x-intercept, y=0. Putting the value ,we get x^2 +x-6 = 0 or x = -3 or 2.
Since the negative x-intercept is required, coordinate will be (-3,0)
Slope of the line passing through (-3,0) and (0,-6) = (0 +6)/(-3-0) = -2
Option A
for y intercept, x = 0. Putting the value we get y=-6. hence the co-ordinate = (0,-6)
For the x-intercept, y=0. Putting the value ,we get x^2 +x-6 = 0 or x = -3 or 2.
Since the negative x-intercept is required, coordinate will be (-3,0)
Slope of the line passing through (-3,0) and (0,-6) = (0 +6)/(-3-0) = -2
Option A
12 Mar 2017, 18:46
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==> From y=x2+x-6=(x+3)(x-2)=0, the x-intercept becomes (-3,0) or (2,0), and (0,-6). From these, the negative x-intercept is (-3,0) and the negative y-intercept is (0,-6). The slope of the straight line that passes through the two points becomes \(\frac{0-(-6)}{-3-0=-2}\)
The answer is A.
Answer: A
The answer is A.
Answer: A
