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29 Mar 2017, 02:24
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
61% (01:37) correct
39%
(01:45)
wrong
based on 365
sessions
History
Date
Time
Result
Not Attempted Yet
How many of the integers that satisfy the inequality (a+1)(a+2)(a+4) ≥ 0 are less than 4?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
0akshay0
Joined: 19 Apr 2016
Last visit: 14 Jul 2019
Posts: 192
Given Kudos: 59
Location: India
Schools: Jindal '20 Kelley '20 Broad '20 Carey '20 Mays '20
GMAT 1: 570 Q48 V22
GMAT 2: 640 Q49 V28
GPA: 3.5
WE:Web Development (Computer Software)
29 Mar 2017, 02:32
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saswata4s
(a+1)(a+2)(a+4) ≥ 0 means when a={-1,-2,-4} the value of (a+1)(a+2)(a+4) = 0
But
when a=0 (a+1)(a+2)(a+4) = 1*2*4 > 0
when a=1 (a+1)(a+2)(a+4) = 2*3*5 > 0
when a=2 (a+1)(a+2)(a+4) = 3*4*6 > 0
when a=3 (a+1)(a+2)(a+4) = 4*5*7 > 0
and when a=-3 (a+1)(a+2)(a+4) = (-2)*(-1)*1 > 0
So 8 integers that satisfy the inequality (a+1)(a+2)(a+4) ≥ 0 which are less than 4
Hence option E is correct
Hit Kudos if you liked it
29 Mar 2017, 02:50
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saswata4s
Solve for the inequality \((a+1)(a+2)(a+4) ≥ 0\) using factor table with sign, we have \(a \in [-4, -2] \cup [-1, +\infty)\)
Since \(a\) is integer and \(a<4\), we have \(a \in \{-4,-3,-2,-1,0,1,2,3\}\)
The answer is E.
