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Bunuel

The circle above has 10 points on its edge. How many different quadrilaterals can be drawn that use four of these points as its vertices?

A. 210
B. 120
C. 60
D. 24
E. 10

Since the circle has 10 points on its edge and we need to create quadrilaterals, each of which has 4 vertices, the number of ways to create those quadrilaterals using the 10 points is:

10C4 = (10 x 9 x 8 x 7)/(4 x 3 x 2 x 1) = 10 x 3 x 7 = 210

Answer: A
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10C4 = 10!/6!4!
210

Answer is A
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The response is 10C4

\(\frac{10}{6!4!}= \frac{10}{1}*\frac{9}{2}*\frac{8}{3}*\frac{7}{4}=210\)
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