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GRE 1: Q169 V154
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Good question Stonecold. 1+2+3+4+5 = 15/3 (Avg of 3) 1...4 = 10/4 (avg of 2.5) Decrease of 0.5

0.5/3 or 5/30 = 1/6 or 16.67%
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stonecold
A set has exactly five consecutive positive integers starting with 1.What is the percentage decrease in the average when the greatest number is removed from the set?

A)5
B)8.5
C)12.5
D)15.2
E)16.6



Source => NOVA.

(10/4)/(15/5)=5/6
1-(5/6)=1/6=16.6 % decrease
E
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stonecold
A set has exactly five consecutive positive integers starting with 1.What is the percentage decrease in the average when the greatest number is removed from the set?

A)5
B)8.5
C)12.5
D)15.2
E)16.6

The original average = (1 + 2 + 3 + 4 + 5)/5 = 3.

The new average = (1 + 2 + 3 + 4)/4 = 2.5

(2.5 - 3)/3 x 100 = -0.5/3 x 100 = -1/6 x 100 ≈ -16.7

We see that the average is decreased by approximately 16.7%.

Answer: E
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A set has exactly five consecutive positive integers starting with 1.

What is the percentage decrease in the average when the greatest number is removed from the set?

Original average = (1+2+3+4+5)/5 =3
Revised average = (1+2+3+4)/4 =2.5

Percentage decrease = .5/3*100% =0.167 =16.67%

IMO E
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